All categories

3 years ago

What is something you learned about in math this week need it for survey

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

5 0

Answer:

we learned very valuble info

Step-by-step explanation:

yes

You might be interested in

Drag the item from the item bank to its corresponding match

Morgarella [4.7K]

You are converting the numbers to a word problem.

1. 5+x = the number five plus x

2. 5-x= the number 5 minus x

3. 5x= five times x

4. 5/x= five divided by x

5. three-fourths of x plus 2

6. two minus three-fourths of x

7. 3 times x plus 10

8. ten times x plus three

5 0

4 years ago

Lisa has a certain amount of money.

vodomira [7]

So what,there is no question here

5 0

3 years ago

Marla has a piece of felt that is 1/3 of a large circle. She cuts the piece of felt in half from the center point of the circle.

LekaFEV [45]

1/3 of the large circle, assuming like 1/3 like pizza cut
then cut into 1/2 of that, assuming again like pizza cut

1/2 of what it was=1/2 of 1/3=1/6 of original

original=whole circle
1/6 of whole circle=1/6 of 360=360/6=60

answer is 60 degrees

6 0

3 years ago

Executives at a large multinational company are being accused of spending too much time on email and not enough time with their

Elena L [17]

Answer:

We conclude that there is not enough evidence to support the claim that company is spending too much time on email.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 96 minutes

Sample mean, $\bar{x}$ = 91 minutes

Sample size, n = 100

Alpha, α = 0.05

Sample standard deviation, s = 25 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu \leq 96\text{ minutes}\\H_A: \mu > 96\text{ minutes}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{91 - 96}{\frac{25}{\sqrt{100}} } = -2$

Now, $t_{critical} \text{ at 0.05 level of significance, 99 degree of freedom } = 1.6603$

Since,

The calculated test statistic is less than the critical value, we fail to reject the null hypothesis and accept it.

Thus, we conclude that there is not enough evidence to support the claim that company is spending too much time on email.

6 0

4 years ago

3. Let U and V be subspaces of a vector space W. Prove that their intersection UnV is also a subspace of W

kenny6666 [7]

Answer: The proof is done below.

Step-by-step explanation: Given that U and V are subspaces of a vector space W.

We are to prove that the intersection U ∩ V is also a subspace of W.

(a) Since U and V are subspaces of the vector space W, so we must have

0 ∈ U and 0 ∈ V.

Then, 0 ∈ U ∩ V.

That is, zero vector is in the intersection of U and V.

(b) Now, let x, y ∈ U ∩ V.

This implies that x ∈ U, x ∈ V, y ∈ U and y ∈ V.

Since U and V are subspaces of U and V, so we get

x + y ∈ U and x + y ∈ V.

This implies that x + y ∈ U ∩ V.

(c) Also, for a ∈ R (a real number), we have

ax ∈ U and ax ∈ V (since U and V are subspaces of W).

So, ax ∈ U∩ V.

Therefore, 0 ∈ U ∩ V and for x, y ∈ U ∩ V, a ∈ R, we have

x + y and ax ∈ U ∩ V.

Thus, U ∩ V is also a subspace of W.

Hence proved.

7 0

3 years ago