Answer:
The slope of the line can be determined from the gradient equation, rise (y axis)/ run (x-axis)
Hence let (-1, 8) be A and (2, -4) be B. The slope from A to B is (-4-8)/(2-(-1))= (-12)/3= -4
Hence the gradient/ slope of the line is -4.
Step-by-step explanation:
Solution:
1) Rewrite it in the form {a}^{2}-2ab+{b}^{2}, where a={d}^{2} and b=4
{({d}^{2})}^{2}-2({d}^{2})(4)+{4}^{2}
2) Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}
{({d}^{2}-4)}^{2}
3) Rewrite {d}^{2}-4 in the form {a}^{2}-{b}^{2} , where a=d and b=2
{({d}^{2}-{2}^{2})}^{2}
4) Use Difference of Squares: {a}^{2}-{b}^{2}=(a+b)(a-b)
{((d+2)(d-2))}^{2}
5) Use Multiplication Distributive Property: {(xy)}^{a}={x}^{a}{y}^{a}
{(d+2)}^{2}{(d-2)}^{2}
Done!
Answer:
What's the problem?
Step-by-step explanation:
No picture or you don't say anything.
Answer:
the value of m = 28°
Step-by-step explanation:
the sum of adjacent angles which form linear pair is 180°
so,
=》3m - 6° + 3m + 18° = 180°
=》6m + 12° = 180°
=》6m = 180° - 12°
=》m = 168° ÷ 6
=》m = 28°
Answers:
CB = 14
GF = 8
FB = 9
EF is parallel to CB
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Explanations:
Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14
For similar reasons, GF is parallel to AC. If AC = 16, then half of that is GF = (1/2)*AC = 0.5*16 = 8.
FB = FA = 9 as these segments have the same single tickmark to indicate they are the same length
EF is parallel to CB because EF is a midsegment, and this is one of the properties of being a midsegment. We can show that quadrilateral EGBF is a parallelogram to help prove this.
