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finlep [7]
3 years ago
10

Find the arc length of the semicircle.

Mathematics
2 answers:
S_A_V [24]3 years ago
5 0

Answer:

9π, or 28.26

Step-by-step explanation:

The Arc of the semicircle is the circumference of half a circle.

The radius of the semicircle is 9, and the circumference of a circle is 2πr, so it is 2π9 = 18π. since this is a semicircle, it is half of that, so 9π, or 28.26, since π is 3.14 here

Tju [1.3M]3 years ago
5 0
Heyoo. I hope this helps! Feel free to ask me any questions if you do not understand what I did.

:)

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The base of the parallelogram, b, can be found by dividing the area by the height.
MaRussiya [10]
The area of a parallelogram is:
 A = b * h
 Where,
 b: base
 h: height
 Clearing the base we have:
 b = A / h
 Substituting values we have:
 b = (6x2 + x + 3) / 3x
 Rewriting we have:
 b = 2x + 1 / x + 1/3
 Answer:
 the length of the base is:
 b = 2x + 1 / x + 1/3
7 0
3 years ago
Read 2 more answers
Solve: x=4+(4x-4)1/2
Damm [24]

Answer:

x = 10

Step-by-step explanation:

x = 4 + (4x-4) ^ (1/2)

First, we rewrite the expression:

x = 4 + (4x-4) ^ (1/2)

x = 2 (2+ (x-1) ^ (1/2))

x = 4 + 2 (x-1) ^ (1/2)

From here we get a solution for x = 10

To check it we substitute x = 10 in the expression:

10 = 4 + 2 (10-1) ^ (1/2)

10 = 4 + 2 (9) ^ (1/2)

10 = 4 + 2 (3)

10 = 4 + 6

10 = 10

Answer:

The solution is:

x = 10

8 0
3 years ago
Read 2 more answers
Find the area of a triangle with a base of 7.5 m and a height of 4*
oksian1 [2.3K]

Answer:

15 units²

Step-by-step explanation:

Hi there!

A=\displaystyle\frac{1}{2} bh where <em>b</em> is the base and <em>h</em> is the height

Plug in the base (7.5) and height (4):

A=\displaystyle\frac{1}{2} (7.5)(4)\\\\A=\displaystyle\frac{1}{2} (30)\\\\A=15

Therefore, the area of the triangle is 15 units².

I hope this helps!

8 0
3 years ago
How do i calculate the first quartile and the third quartile??? <br> !!!please help!!!
diamong [38]

Answer: The Median: 78, The First Quartile: 63, and The Third Quartile: 99

Step-by-step explanation: Ok, so let's put the data set from least to greatest....

(63, 63, 76,) (77, 79,) (84, 99, 99)

First Quartile              Third Quartile

First, let's find the median, since you made a little mistake...

77 + 79 = 156

156 ÷ 2 = 78

The median is 78!

Now, let's determine the first quartile and the third quartile.

For the the first quartile/third quartile it'll be the middle number, if it's even we'll do the same extra step just like we'll do for the median. In this case it's not even therefore...

First Quartile: 63

Third Quartile: 99

I hope this helps!

5 0
3 years ago
Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have?
Nonamiya [84]
0.05n + 0.25q = 1.60
q = 3n

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5n + 75n = 160...answer D

8 0
3 years ago
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