Answer:
First We Will start with the states a claim that can be backed
up with evidence this would be in the strong thesis statement
Next the states facts about the topic that again would be in the strong thesis statement
Next the answers a major question related
to the literary work that would be the last strong thesis statement
focuses on the specific word would be in the weak side and last is open to argument I am sure this would be in the weak section
Step-by-step explanation:
I did the test please mark this brainliest
Hello there!
We've already given the formula so I will not be adding it here.
We are also given that π = 3 for this problem.
r is defined as 'radius'
Radius is a point from center to one of endpoints.
Look at the image, the radius is given as 7cm.
From the information we gathered:
Substitute in the formula.
![\displaystyle \large{ V = \frac{4}{3} (3) {(7)}^{3} }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%20V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%20%283%29%20%7B%287%29%7D%5E%7B3%7D%20%7D)
Cancel 3 out.
![\displaystyle \large{ V = 4{(7)}^{3} }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%20V%20%3D%204%7B%287%29%7D%5E%7B3%7D%20%7D)
Evaluate 7^3
![\displaystyle \large{ V = 4(343) }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%20V%20%3D%204%28343%29%20%7D)
Multiply
![\displaystyle \large{ V = 1372 }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%20V%20%3D%201372%20%7D)
Therefore, the volume is 1372.
Let me know if you have any questions!
Topic: Surface Area and Volume - Sphere's Volume
To solve this problem you must apply the proccedure shown below:
1- By definition, the formula for calculate the i<span>nterquartile range is
I</span><span>nterquartile range=Q3-Q1
Where Q1 is the lower quartile and Q3 is the upper quartile.
2-Keeping this on mind, you have:
</span>Interquartile range=Q3-Q1
<span>
Q3=245
Q1=201
</span>Interquartile range=245-201
Interquartile range=44
<span>
Therefore, the answer is: 44
</span>
Answer:
The change in height is 6/10 miles per hour and the entire descent will last 150 minutes (2 hours and 30 minutes)
Step-by-step explanation:
The gilder started 1 1/2 miles above the ground, in other words, it started
miles above the ground. After 60 minutes it is now
miles above the ground.
Therefore, the change in height in one hour is:
miles.
Now, we know that the glide descends at a rate of 6/10 miles per hour, we can solve the second part of the problem using the rule of three (or proportions)
<em>If it takes it 60 minutes to descend 6/10 miles, how long it will take it to descend 15/10 miles?</em>
60 minutes --- 6/10= .6
x minutes ---- 15/10= 1.5
Therefore
minutes
Thus, the entire descent will last 150 minutes.