Answer:
Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.
Step-by-step explanation:
I just took the quiz, I hope this helps :).
Answer:
Expression: 66(19+14)
Answer: 2178
Step-by-step explanation:
<u>66(19+14)</u>
66(33)
2178
the table below:
Grade In favor Opposed Undecided Total
Grade 9 6 4 8 18
Grade 10 10 11 9 30
Grade 11 12 15 11 38
Grade 12 15 6 14 35
If the principal randomly selects a student in grade 10 from this survey,
the probability that the student is opposed to extending the school day
P ( student in grade 10 is opposed)= Number of student in opposed(grade10) / total number of students in grade 10
Number of student opposed who is in grade10 = 11
total number of students in grade 10 = 30
P( student in grade 10 is opposed)= 
= 0.37
the probability that the student is opposed to extending the school day= 0.37
Answer:
(-3, 3) and (8, -8)
Step-by-step explanation:
having the rule (x + 3, y – 5) and an input point (x,y) you just plu th iput point into the rule and you will get the output point.
With an input point (-6,8) you plug -6 in for x and 8 in for y into the rule.
(x + 3, y – 5)
(-6 + 3, 8 - 5)
(-3, 3)
Now we do the same for (5, -3) as the input
(x + 3, y – 5)
(5 + 3, -3 - 5)
(8, -8)
Answer:
3/5
Step-by-step explanation:
There are 20 balls, numbered 1 through 20.
Of these, 10 are even, 4 are less than five, and 2 are both even and less than 5.
So the probability is:
P(even or <5) = P(even) + P(<5) − P(even and <5)
P(even or <5) = 10/20 + 4/20 − 2/20
P(even or <5) = 12/20
P(even or <5) = 3/5
