Answer:
Option (B)
Step-by-step explanation:
To calculate the distance between C2 and SW1 we will use the formula of distance between two points 
and 
.
d = 
Coordinates representing positions of C2 and SW1 are (2, 2) and (-6, -7) respectively.
By substituting these coordinates in the formula,
Distance between these points = 
= 
= 
units
Therefore, Option (B) will be the correct option.
Well, I saw my teacher solving the test herself, and then grading papers off of her paper that she solved. My teacher made the answer key for the tests.
If you use the FOIL (first, outer, inner, last) method when factoring its much easier then you can add like terms
Step-by-step explanation:
D= 56t
D= 60t -2
D= Distance T=time d = 56t (Jordan) d = 60t - 2 (Roman)
d = 56t d = 60t - 2
56t = 60t - 2 d = 56(1/2) d = 60(1/2) - 2
-60t -60t d = 28 d = 30 - 2 = 28
-4t = -2
t = 1 / 2
Answer:
2
Step-by-step explanation:
Step 1. <em>Find a coterminal angle that falls be 0 and 2π.
</em>
Remember that cscθ is a periodic function. It repeats every 2π radians.
If n is an integer, cscθ = csc(θ ± 2πn)
csc(17π/6) = csc(12π/6 + 5π/6)
= csc(2π + 5π/6)
= csc(5π/6)
Step 2. <em>Use the unit circle to evaluate cscθ.
</em>
cscθ = 1/sinθ
Let θ = 5π/6
In a unit circle (below), the sine of an angle is y.
sinθ = ½
cscθ = 1/sinθ
= 1/(½)
= 2
