Let t be time in hours.
Train A travels at 100 km per hour, so after t hours it will be 100t km from the station.
Train B travels at 160 km per hour, but it leaves the station one and a half hours later than train A, so its time is (t-1.5) hours. After (t-1.5) hours it will be 160(t-1.5) km from the station.
Train B will overtake train A when their distances from the station are equal.

Train B will overtake train A after 4 hours since train A left the station. It left the station at 8:00, so train B will overtake it at
12:00.
when solving for y
y = -7x/3-6
so y does not vary directly with x
the answer is no
0.578 rounded to the nearest tenth would be 0.6, since the 7 in the hundredths spot is higher than 5.
I think it’s Step 2 your welcome
Answer:
tan=Opposite/Adjacent so 3/4 is the answer
Step-by-step explanation:
3 is opposite of A and 4 is Adjacent of A
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