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aliina [53]
3 years ago
12

What is the solution to the equation 9^-3x = 7? (1 point)

Mathematics
1 answer:
babymother [125]3 years ago
7 0

Answer:

take In of both sides or log of both sides

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Please help and explain
bagirrra123 [75]

Answer:

See below

Step-by-step explanation:

The three angles inside of the triangle sum to 180

11x + 4       + 3x      + 78 = 180

14x +82 =180

x = 7

then B =   11x + 4    = 11(7) + 4 = 81 degrees

C =  3x = 21 degrees

5 0
2 years ago
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What’s the total badges and buy all the Boy Scouts<br> 26<br> 25<br> 52<br> 78
amid [387]
78 . Hope this was helpful
4 0
3 years ago
Ratio in lowest terms <br> 45 girls and 30 boys
drek231 [11]
3:2 is ur answer to this question
6 0
3 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
Integrate the following. ∫<img src="https://tex.z-dn.net/?f=5x%5E%7B4%7D%20dx" id="TexFormula1" title="5x^{4} dx" alt="5x^{4} dx
Vadim26 [7]

Answer:

\displaystyle D)  {x}^{5}  +  \rm C

Step-by-step explanation:

we would like to integrate the following Integral:

\displaystyle \int 5 {x}^{4} \, dx

well, to get the constant we can consider the following Integration rule:

\displaystyle \int c{x} ^{n}  \, dx  =  c\int  {x}^{n}  \, dx

therefore,

\displaystyle 5\int  {x}^{4} \, dx

recall exponent integration rule:

\displaystyle \int {x} ^{n}  \, dx  =  \frac{ {x}^{n + 1} }{n + 1}

so let,

  • n = 4

Thus integrate:

\displaystyle  =  5\left( \frac{ {x}^{4+ 1} }{4 +  1}  \right)

simplify addition:

\displaystyle  =  5\left( \frac{ {x}^{5} }{5}  \right)

reduce fraction:

\displaystyle  =  {x}^{5}

finally we of course have to add the constant of integration:

\displaystyle  \boxed{ {x}^{5}  +  \rm C}

hence,

our answer is D)

7 0
3 years ago
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