Answer:
<u>The width of the rectangle is 4.8 inches</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Area of the rectangle = 12 square inches
Length of the rectangle = 2.5 inches
2. What is the width?
We will find out the width, this way:
Width * Length = Area of the rectangle
Replacing with the real values, we have:
Width * 2.5 = 12
Width = 12/2.5
<u>Width of the rectangle = 4.8 inches</u>
The intersection point of the two lines is (2,1,0).
The respective direction vectors are
L1: <1,2,4>
L2: <4,1,15>
Since the normal vector of the required plane is perpendicular to both direction vectors, the normal vector of the plane is obtained by the cross product of L1 and L2.
i j k
1 2 4
4 1 15
=<30-4, 16-15, 1-8>
=<26, 1, -7>
We know that the plane must pass through (2,1,0), the equation of the plane is
26(x-2)+1(y-1)-7(z-0)=0
simplifying,
26x+y-7z=52+1+0=53
or
26x+y-7z=53
Check:
Put points on L1 in the plane
26(t+2)+(2t+1)-7(4t+0)=53 ok
For L2,
26(4t+2)+(t+1)-7(15t+0)=53 ok
39.5 %
39.5 / 100
39 1/2 / 100
79/2 / 100
79 / 200
Hopefully these are correct lol, make sure to check it with a classmate. but i tried :)
Answer:
The distance formula is 
The midpoint formula is 
Step-by-step explanation:
apply the pythagorean theorem on a coordinate grid
