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2 years ago

Which expression is equivalent to the expression shown?

Mathematics

1 answer:

Basile [38]2 years ago

4 0

Answer:

5^0

Step-by-step explanation:

(5^3)^9 = 3 + 9 = 12

= 5^12

5^12/5^12 = 12 - 12 =0

5^0

brainliest is appreciated

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NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions

Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector $\vec{v}$ in some vector space $\mathbb R^n$ we have

$\vec{v} = \langle a,b\rangle$

This is the component form. I don't like that way. It is probably used in high school, but

$\vec{v} = \begin{pmatrix} a\\ b\\ \end{pmatrix}$

is preferable because the inner product on $\mathbb R^n$ is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as $\vec{v} = 2i+2j$

For this question, I think you meant

vectors

$\vec{u_1} = (-8, 12)$

$\vec{u_2} = (13, 15)$

Once

$\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}$

Considering that the dot product is

$\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76$

and the norm of $\vec{u_1}$ is $||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}$

and the norm of $\vec{u_2}$ is $||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}$

Thus,

$\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}$

$\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)$

3 0

2 years ago

What is the solution to the equation -4 - 2=46

ch4aika [34]

-4 -2 = -4 + (-2) = -6

As you see here, -6 does not equal 46, therefore, this equation has no solution.

-6 ≠ 46

Final answer:- No solution to this equation.

4 0

3 years ago

Read 2 more answers

(9, 8) is the midpoint of mc136-1.jpg. The coordinates of S are (10, 10). What are the coordinates of R?

kolbaska11 [484]

I cant see the image...but I take it that the midpoint is (9,8) and the endpoint S is (10,10) and ur looking for the other endpoint R.

midpoint formula : (x1 + x2) / 2, (y1 + y2) / 2
(10,10)....x1 = 10 and y1 = 10
(x,y)....x2 = x and y2 = y
so we sub
(10 + x) / 2, (10 + y) / 2 = 9/8

(10 + x) / 2 = 9
10 + x = 9 * 2
10 + x = 18
x = 18 - 10
x = 8

(10 + y) / 2 = 8
10 + y = 8 * 2
10 + y = 16
y = 16 - 10
y = 6

so endpoint R has coordinates of (8,6) <===

7 0

3 years ago

FInd the GCF of the numbers using prime factorizations.

lesya [120]

Answer:

GCF(330, 75, 450, 225) = 15

Steps:

Prime factorization of the numbers:

330 = 2 × 3 × 5 × 11

75 = 3 × 5 × 5

450 = 2 × 3 × 3 × 5 × 5

225 = 3 × 3 × 5 × 5

GCF(330, 75, 450, 225)

= 3 × 5

= 15

3 0

3 years ago

I need to know the Salary and explain how you got it.

RideAnS [48]

WEEKLY Earning Full time = 40 h x $15 = $600/week
Over time = 3 h 25 min or 3h + 25/60 h
WEEKLY Earning Over time = (3 h)x $30 + (25/60) x $30 = $115

TOTAL WEEKLY INCLUDING OVERTIME: = $715
TOTAL SEMI MONTHLY INCLUDING OVERTIME =$715 X2 = $1,430
BIWEEKLY = SEMI MONTHLY = $1,430
TOTAL MONTHLY INCLUDING OVERTIME =$715 x 4 = $2,860

8 0

2 years ago