2 years ago

HELPPPP looks at the image and EXPLAIN

Mathematics

2 answers:

Alinara [238K]2 years ago

8 0

Answer:

The answer is D

Step-by-step explanation:

160 is 4 times more the 40 so 57 time 4 is 228

denis-greek [22]2 years ago

3 0

Answer: 228

Step-by-step explanation:

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What is -4 3/4+2 1/2

OLga [1]

The answer as a mixed number: -2 1/4
the answer as a decimal: -2.25
the answer as an improper fraction: -9/4

3 0

3 years ago

S = 1 / g t ² π, solve for t

Finger [1]

$s = \frac{1}{g {t}^{2}\pi }$

multiply through by

$g {t}^{2} \pi$

$s \times g {t}^{2} \pi = \frac{1}{g {t}^{2} \pi} \times g {t}^{2} \pi$

$sg {t}^{2} \pi = 1$

dividing through by

sgπ

${t}^{2} = \frac{1}{sg\pi}$

$t = \sqrt{ \frac{1}{sg\pi} }$

4 0

3 years ago

Read 2 more answers

Using the proportion 2/5=y/100 which equation can be used to find the value of Y

natulia [17]

2/5 = y/100
40/100 = y/100
Y=40

4 0

2 years ago

A certain radioactive material decays in such a way that the mass in kilograms remaining after t years is given by the function

Angelina_Jolie [31]

The mass of radioactive material remaining after 50 years would be 48.79 kilograms

<h3>How to determine the amount</h3>

It is important to note that half - life is the time it takes for the amount of a substance to reduce by half its original size.

Given the radioactive decay formula as

m(t)=120e−0.018t

Where

t= 50 years

m(t) is the remaining amount

Substitute the value of t

$m(t) = 120e^-^0^.^0^1^8^(^5^0^)$

$m(t) = 120e^-^0^.^9$

Find the exponential value

m(t) = 48.788399

m(t) = 48.79 kilograms to 2 decimal places

Thus, the mass of radioactive material remaining after 50 years would be 48.79 kilograms

Learn more about half-life here:

brainly.com/question/26148784

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1 year ago

What are all the true statements

Finger [1]

Answer:

i am going to say number 1 even though they all sound right hope i helped <3

Step-by-step explanation:

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3 years ago