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3 years ago

Two samples of fish from a pond were analyzed. The second sample was taken six months after the first sample.

Mathematics

2 answers:

Agata [3.3K]3 years ago

8 0

Answer:

Step-by-step explanation:

Lorico [155]3 years ago

8 0

Answer:

B,D,E

Step-by-step explanation:

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A physician orders a dosage of 85mg. The drug on hand is labeled “0.1g in 1.5mL”. How many ML should the pharmacy technician giv

marin [14]

Answer:

Step-by-step explanation:

0.1 g = 100 mg

85 mg / 100 mg = x mL / 1.5 mL

x = 1.275 mL

7 0

2 years ago

Compare the pair of fractions. ( <,>,=) <br> 3/4__5/6

Andrew [12]

Answer:

3/4 is less < than 5/6

Step-by-step explanation:

4 0

3 years ago

Solve for e.<br><br> 4/3=-6e-5/3

cricket20 [7]

Answer:

e = 1/2

Step-by-step explanation:

to solve foe e in this 4/3=-6e-5/3

solution

4/3=-6e-5/3

4/3 + 5/3 = 6e

find the lcm of the left hand side

4 + 5/3 = 6e

9/3 = 6e

cross multiply

3 x 6e = 9 x 1

18e = 9

divide both sides by the coefficient of e which is 18

18e /18 = 9/18

e = 1/2

therefore the value of e in the expression above is evaluated to be equals to 1/2

5 0

3 years ago

Jaxson buys ice cream and apples at the store. He pays a total of $24.81. He pays a total of $3.60 for the ice cream. He buys 7

Vadim26 [7]

Answer:

$3.03

Step-by-step explanation:

7x + $3.60 = $24.81

Subtract $3.60 from both sides of the equation:

7x + $3.60 - $3.60 = $24.81 - $3.60

7x = $24.81 - $3.60

7x = $21.21

Divide each side by 7:

(7x/7) = ($21.21/7)

x = ($21.21/7)

x = $3.03

3 0

3 years ago

Classify ABC by its sides. Then determine whether it is a right triangle.

m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

$AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

AB = $\sqrt{(9-3)^{2}+(6-3)^{2} } = \sqrt{6^{2}+3^{2} } =\sqrt{45}$

Given vertices are B(6,9) and C( 6,-3)

$B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

= $\sqrt{(-3-9)^{2}+(6-6)^{2} } =\sqrt{12^{2} } = 12$

BC = 12

Given vertices are A(3,3) and C( 6,-3)

$AC = \sqrt{(6-3)^{2}+(-3-3)^{2} } = \sqrt{9+36} = \sqrt{45}$

AC² = AB²+BC²

45 = 45+144

45 ≠ 189

∴Given Δ ABC is not a right angle triangle

5 0

3 years ago