Answer:
<h3><ABC > <DBC.</h3>
Step-by-step explanation:
Given < DBC = < RST and we need to prove < ABC is greater than <RST.
First given statement:
< DBC = < RST
Reason: Given.
Second given statement :
<ABC = <DBC+ <ABD.
Reason: Angle addition theorem.
<em>Note: < ABC is the sum of angles <DBC and <ABD and we have < DBC = < RST. So it's an obvious thing that the sum of angles <DBC and <ABD is always greater than <RST.</em>
Also, <ABC is greater than <DBC.
Therefore, correct option for third statement is :
<h3><ABC > <DBC.</h3>
Answer:
10
Step-by-step explanation:
First make the fractions the same value:
3 and 3/4s is equal to
15/4 which is 30/8s
So,
10 3/8s go into 30/8s
<span>√3 * 2√2 * 5√8 * 18
2 x 5 x 18
10 x 18
180
</span>√3 x √2 x √8 =
√6 x √8 =
√48
√48 = 6 x 8 = 3 x 2 x 2 x 2 x 2 = 4√3
180 x 4√3 = 720√3
720√3 should be your answer
hope this helps
First, you have to find the median, which is the number in the middle: 25
Then cut the data in half by the median, so your new data sets are
15,29,20
and
31,38,41
Now you find the median of both of those sets, which is 29 and 38.
The interquartile range is the difference between the numbers, so 38-29 = 9.
