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Alexus [3.1K]
3 years ago
6

What is the y-intercept of the line y = 2/3x + 2?

Mathematics
2 answers:
vlada-n [284]3 years ago
8 0

Answer: 2

Step-by-step explanation:

From the equation y=mx+c

m is the slope and c is the y intercept of the the line which is y

So y=(2/3)x +2

m=2/3

c= 2

Andrej [43]3 years ago
3 0

Answer:

2

Step-by-step explanation:

y=mx+b

m is slope b is the y-intercept

so in y=2/3x+2

2/3 is the slope

2 is the y-intercept

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Ms. Brack wants to hang a bulletin board with
Eduardwww [97]

Answer:

He needs 8.75 ft² polka dot paper to cover the board.

Step-by-step explanation:

How much polka dot paper she need to cover the board is the area of the board . The is a rectangle with length 3.5 ft long and width of 2.5 ft wide .

The area of the board(rectangle) = length × width

Area = LW

where

L= 3.5 ft

W = 2.5 ft

Area = 3.5 × 2.5

Area = 8.75 ft²

He needs 8.75 ft² polka dot paper to cover the board.

7 0
3 years ago
Evaluating integral by net area
N76 [4]

The graph of f(x)=2 is a horizontal line. So the area under f(x) on [0, 8] is equal to the area of a rectangle with length 8 and height 2, or 16.

The graph of g(x)=\sqrt{64-x^2} is the upper half of a circle with radius \sqrt{64}=8. It's symmetric about x=0, so on the interval [0, 8], we're considering a quarter of the circle. The area of such a sector is \frac{\pi 8^2}4=16\pi.

Then use the fact that the definite integral is distributive over sums, meaning

\displaystyle\int_0^8f(x)+g(x)\,\mathrm dx=\int_0^8f(x)\,\mathrm dx+\int_0^8g(x)\,\mathrm dx=16+16\pi

8 0
3 years ago
Determine which number has a greater magnitude."<br><br> 7 and -8
MariettaO [177]

Answer:

7

Step-by-step explanation:

-8 is a negative number for example if you have -8 and you wanna get it to 0 you add 8 you don't have to do that with 7 it's a "positive" number

3 0
3 years ago
Read 2 more answers
GIVING BRAINLIEST!! HELP PLEASE!! you don't have to make it perfect. (no links/spam/or stealing points. i will report your accou
choli [55]
<h2>Answer:</h2>

C = 2πr

r = C/2π ...(1)

A = πr²

A = π(C/2π)² = πC²/4π²

A = C²/4π.

<u>Correct choice</u> - [A] A = C²/4π.

6 0
3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
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