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wariber [46]
3 years ago
9

There are approximately 7.5x10^18 grains of sand on earth.There are approximately 7x10 ^27 atoms in an average human body.Are th

ere more grains of sand on earth or atoms in an average human body ?How do you know?
Mathematics
1 answer:
Likurg_2 [28]3 years ago
5 0
They are more atoms in a body, only 75,000,000,000,000,000,000 grains of sand
and
7,000,000,000,000,000,000,000,000,000
atoms in a body, at the end , the number of atoms seem longer and larger.
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A game contains 3 bags of green chips 2 bags of red chips and 5 bags og yellow chips. there ard 25 green chips in a bag and 30 r
nika2105 [10]
1 game has 3 bags of green chips ; 2 bags of red chips ; 5 bags of yellow chips
1 bag: 25 green chips
1 bag: 30 red chips

total number of chips:
green: 3 x 25 = 75 
red: 2 x 30 = 60
yellow: 75 + 60 = 135  answer to part a.

75 + 60 + 135 = 270 total number of chips.

270 / 54 = 5 players. answer to part b.

Each of the 5 players will have 15 green chips, 12 red chips, and 27 yellow chips, for a total of 54 chips.
8 0
2 years ago
An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object
Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2  + \frac{1}{2} at^2\\3) v = v_0 + at

What do we already know?

  • v_0 = 29.4 ms^-1
  • The launch is straight up
  • a = -9.81 ms^-2 this is the gravitational acceleration g
  • s_0 = 0 m, since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, v = 0 ms^-2

v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2

this is the equation of the whole trajectory that object makes.

and if you solve this by making s = 0, you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

5 0
3 years ago
Whats 3,684,266 to the nearest hundred thousand and million
grin007 [14]
The nearest hundred thousand is 3,700,000
And the nearest million is 4,000,00
4 0
3 years ago
MATH............................................................
stira [4]

Answer:

For A its 10 Feet because if each  unit is 5 feet and there are 2 units then its 10 feet and then B is 35 because seven units means 5 x 7 then 35feet is the answer

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Circle equal groups.write an equivalent fraction for the shaded part of the whole
zlopas [31]

Answer:

1/2

Step-by-step explanation:

The answer is 1/2 because the fraction 4/8 can be simplified into 1/2 because they are the same.

3 0
2 years ago
Read 2 more answers
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