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elixir [45]
3 years ago
13

Help for brainlest if right

Mathematics
1 answer:
Naddika [18.5K]3 years ago
7 0
I think it’s B. 2x9 is 18. then 18 times 15.
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Mark rolls 2 fair dice and adds the results from each. Work out the probability of getting a total of 5. Please help if you can!
Allisa [31]

Answer:

13.8%

Step-by-step explanation:

I have created a table that shows all of the possibilities that two die's can roll when summed up. If we count all of these possibilities we can see that there are a total of 36 outcomes. From all of these outcomes we can also see that only 4 outcomes sum up to be a total of 5. Therefore, we have to divide the number of times 5 is a possibility by the total number of outcomes to get the probability of actually getting a sum of 5.

5 / 36 = 0.138  ... multiply by 100 to get percentage

0.138 * 100 = 13.8%

3 0
3 years ago
Write a recursive formula for the arithmetic sequence below. What is the value of the 8th term?
Bumek [7]
To find the answer,

Multiply the term with 4 then subtract with 3

Lets take the term as 'n'

Formula = 4n-3

Value of 8th term = (4*8)-3
                            = 32-3
                            = 29

The value of 8th term is 29
4 0
4 years ago
Read 2 more answers
find an equation of the tangent plane to the given parametric surface at the specified point. x = u v, y = 2u2, z = u − v; (2, 2
Alexxandr [17]

The surface is parameterized by

\vec s(u,v) = x(u, v) \, \vec\imath + y(u, v) \, \vec\jmath + z(u, v)) \, \vec k

and the normal to the surface is given by the cross product of the partial derivatives of \vec s :

\vec n = \dfrac{\partial \vec s}{\partial u} \times \dfrac{\partial \vec s}{\partial v}

It looks like you're given

\begin{cases}x(u, v) = u + v\\y(u, v) = 2u^2\\z(u, v) = u - v\end{cases}

Then the normal vector is

\vec n = \left(\vec\imath + 4u \, \vec\jmath + \vec k\right) \times \left(\vec \imath - \vec k\right) = -4u\,\vec\imath + 2 \,\vec\jmath - 4u\,\vec k

Now, the point (2, 2, 0) corresponds to u and v such that

\begin{cases}u + v = 2\\2u^2 = 2\\u - v = 0\end{cases}

and solving gives u = v = 1, so the normal vector at the point we care about is

\vec n = -4\,\vec\imath+2\,\vec\jmath-4\,\vec k

Then the equation of the tangent plane is

\left(-4\,\vec\imath + 2\,\vec\jmath - 4\,\vec k\right) \cdot \left((x-2)\,\vec\imath + (y-2)\,\vec\jmath +  (z-0)\,\vec k\right) = 0

-4(x-2) + 2(y-2) - 4z = 0

\boxed{2x - y + 2z = 2}

6 0
2 years ago
Which of the following functions is graphed below
Nady [450]
Not sure but my guess is answer B but you might want to check around be for taking my advice on this.
3 0
4 years ago
Read 2 more answers
Four movie tickets cost $26.00. How much do seven movie tickets cost.
umka21 [38]
4 = $26

26/4 = $6.50
1 ticket = $6.50
6.5 x 3 =19.50

26+19.50 = 45.50

7 tickets = $45.50

4 0
3 years ago
Read 2 more answers
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