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goldenfox [79]
3 years ago
5

Helppppp a. 90 b. 85 c. 75 d. 115

Mathematics
1 answer:
serious [3.7K]3 years ago
3 0

Answer:

85is the correct answer

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Help with these math exercises, please!
lions [1.4K]
1) (3-x) x (3+x)

2) 5(5-x) x (5+x)

3) (3v-wy) x (3v+wy)

4) 2(k-m) x (k+m) x (k^2+m^2)

5) (ab-4c) x (ab+4c)

Brainliest?
4 0
3 years ago
If the area of a rectangle with length (4x) is 4x2 + 12x, find the width.​
8090 [49]

Answer:

The width of a rectangle is: w = x+3

Step-by-step explanation:

Given

The length of rectangle = l = 4x

The area of rectangle = A = 4x² + 12x

To determine

The width of rectangle = w = ?

We know that the formula of the area of the rectangle is

A = wl

substitute A = 4x² + 12x and l = 4x in the equation to determine the width w of the rectangle

4x² + 12x = w×4x

w = [4x² + 12x] / [4x]

Factor 4x² + 12x:   4x(x+3)

w = [ 4x(x+3) ] /  [4x]

w = x+3

Therefore, the width of a rectangle is: w = x+3

3 0
3 years ago
The heights of women aged 20 to 29 are approximately normal with mean 64 inches and standard deviation 2.7 inches. Men the same
san4es73 [151]

Answer:

Step-by-step explanation:

Z=\frac{x-mu}{\sigma }

X - Heights of women aged 20 to 29: X is N(64, 2.7)

Y - Heights of men aged 20 to 29: X is N(69.3, 2.8)

a) X=6'=72"

Z=\frac{72-64}{2.7} =2.963

b) Y = 72"

z=\frac{72-69.3}{2.8} =0.965

c) 72' women can be taken as very tall but men moderately taller than average

d) Y<5'5" =65"

Z<\frac{65-69.3}{2.8} =-1.536

e) X>73"

Z>\frac{73-64}{2.7} =3.33

Almost 0% can be taken

f) IQR =Q3-Q1

Z scores =

5 0
3 years ago
10-11 PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!
AnnZ [28]
10-11= -1 You could also input this number on a calculator
6 0
3 years ago
Combine these radicals. 8√5 + 2√45
Greeley [361]
<span>8√5 + 2√45
= </span><span>8√5 + 6√5
= 14</span>√5

hope it helps
8 0
3 years ago
Read 2 more answers
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