The expected value per game is -0.26. Over 1000 games, you can expect to lose $263.16.
To find the expected value, we multiply the probability of winning by the amount of winnings, the probability of losing by the amount of loss, and adding those together.
We have a 1/38 chance of winning; 1/38(175) = $4.61. We also have a 37/38 chance of losing; 37/38(5) = $4.87.
$4.61-$4.87 = -$0.26 (rounded)
To five decimal places, our answer is -0.26136; multiplied by 1000 games, this is $261.36 lost.
I think it is option 1 sorry if wrong
Answer:
<h2><em><u>n</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em></h2>
Step-by-step explanation:
4(n-1)+2 = -23 +7n
=> 4n - 4 + 2 = - 23 + 7n
=> 23 - 4 + 2 = 7n - 4n
=> 21 = 3n

=> <em><u>n</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>