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3 years ago

Which equation requires the multiplication property of equality to be solved?

Mathematics

2 answers:

alexira [117]3 years ago

6 0

Option 1: 6a = 420 requires division property of equality to be solved
Step-by-step explanation:
Solving an equation means to find the value of a variable by isolating the variable on one side of the equation.
We will see all the options one by one.
Option 1:

In this option, 6 is multiplied with the variable so we have to divide the whole equation by 6 to find the value of a.
So we will use "Division property of Equality"
Dividing both sides by 6

pls help me get Brainlyest

polet [3.4K]3 years ago

3 0

Answer:

I think it would be a-6=420 but I'm not really sure

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A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes

$\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}$

hence the answer is 0.4823

(iii) All are defective

$\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}$

(iv) At least one is defective

This is 1 - probability that none is defective

$\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}$

Hence the answer is 0.5177

3 0

1 year ago

How do I do this help please

elena55 [62]

Answer:x=3

Step-by-step explanation:

Add 4 to both sides and get 3x=5+4

Simplify 5+4 to 9 and get 3x=9

Divide both sides by 3 and get x=9/3

Simplify 9/3 to 3 and get the answer x=3

4 0

3 years ago

How do i write a two column proof for this?? Given: PG ≅ SG and PT ≅ ST . Prove: ∠GPT ≅ ∠GST

Nikolay [14]

Answer:

PG ≅ SG (Given)

PT ≅ ST (Given)

GT = GT (Common)

∴ ∠GPT ≅ ∠GST (SSS Congruency Axiom)

Step-by-step explanation:

Given: PG ≅ SG and PT ≅ ST

To Prove: ∠GPT ≅ ∠GST

Proof: PG ≅ SG (Given)

PT ≅ ST (Given)

GT = GT (Common)

∴ ∠GPT ≅ ∠GST (SSS Congruency Axiom).

SSS Congruency Axiom: If three pairs of sides of two triangles are equal in length, then the triangles are congruent.

Congruence: Two sets of points are called congruent if, and only if, one can be transformed into the other by an isometry, i.e., a combination of rigid motions, namely a translation, a rotation, and a reflection. This means that either object can be repositioned and reflected (but not resized) so as to coincide precisely with the other object. Two triangles are congruent if their corresponding sides are equal in length, and their corresponding angles are equal in measure.

7 0

4 years ago

1. If RU = 16, UT = 20, and SR = 16, what is the perimeter of SUT?

nlexa [21]

Answer:

Step-by-step explanation:

If SR and RU have the same length, a right angle, and a shared side, we know that they are congruent triangles using SAS (Side Angle Side). Our equation to find the perimeter would be SR + RU + UT + TS or 16 + 16 + 20 + 20(using our knowledge of the congruent triangles) = 72.

6 0

3 years ago

These rational expressions all have the same denominator write the sum of their numerators over the common denominator 2x+1 + x

ale4655 [162]

So if all same you just simplify The top : 2x+1+x+4 2x+x+1+4 3x+5 The bottom all same just use one .x-3 3x+5/x-3

8 0

3 years ago

Read 2 more answers