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Zepler [3.9K]
3 years ago
12

What causes objects sliding on a surface to stop?

Chemistry
1 answer:
MAXImum [283]3 years ago
8 0

Answer:c

Explanation: becasue if u add to it u get 5 or c

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In the Beer-Lambert Law equation, what does the “b” represent?
Mkey [24]
The answer is Thickness of solution.

The Beer-Lambert Law equation has the following form:

A=E×b×c

Where A is absorbance, E <span>is the molar absorbtivity, </span>b is the path length of the sample and c <span>is the concentration of the compound in solution.
</span>
<span>Lamber-Ber's law shows that the absorbance of a solution is directly proportional to the concentration of the species to be absorbed, as well as the length of the path. For example, if the length of the path is constant, the UV / VIS spectroscopy can be used to determine the concentration of the absorbent substance in the solution.</span>


6 0
4 years ago
Read 2 more answers
Carbon is one of the most common elements found in living things
zzz [600]

Answer:

Major Elements

The six most common elements inliving things are carbon, hydrogen, oxygen, nitrogen, phosphorus, and sulfur. Atoms of these elementscombine and form thousands of large molecules. These large molecules make up the structures of cells and carry out many processes essential to life.

4 0
3 years ago
If a body of water has high turbidity levels, what can most likely be concluded?
harina [27]
Unsafe to dono because it’s way too high
6 0
3 years ago
What atom has 48 neutrons,and 32 protons
Mekhanik [1.2K]
Germanium as it has 32 protons
8 0
4 years ago
Read 2 more answers
Upon adding solid potassium hydroxide pellets to water the following reaction takes place: KOH(s) → KOH(aq) + 43 kJ/mol Answer t
nekit [7.7K]

Answer:

a) Warmer

b) Exothermic

c) -10.71 kJ

Explanation:

The reaction:

KOH(s) → KOH(aq) + 43 kJ/mol

It is an exothermic reaction since the reaction liberates 43 kJ per mol of KOH dissolved.

Hence, the dissolution of potassium hydroxide pellets to water provokes that the beaker gets warmer for being an exothermic reaction.

The enthalpy change for the dissolution of 14 g of KOH is:

n = \frac{m}{M}

<u>Where:</u>

m: is the mass of KOH = 14 g

M: is the molar mass = 56.1056 g/mol

n = \frac{m}{M} = \frac{14 g}{56.1056 g/mol} = 0.249 mol

The enthalpy change is:

\Delta H = -43 \frac{kJ}{mol}*0.249 mol = -10.71 kJ

The minus sign of 43 is because the reaction is exothermic.

I hope it helps you!

5 0
3 years ago
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