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3 years ago

What do all the elements in group 2 of the periodic table have in common

Chemistry

2 answers:

IgorLugansk [536]3 years ago

8 0

Answer:

tend to form ionic bonds by losing electrons making these atoms positive charge.

Explanation:

Hoochie [10]3 years ago

8 0

They are all alkaline earth metals

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What is the percentage of water in the hydrate CoCl2 • 6H2O? Can someone help me with this one?

valkas [14]

Okay, to do this you have to work with the relative molecular mass (RMM). You can get this from looking at the periodic table.

The RMM for the whole molecule is:
58.933 + (2 x 35.453) + (12 x 1.008) + (6 x 15.9994) = 237.96

Then you work out the RMM for water:
(2 x 1.008) + 15.9994 = 18.0154

As there are 6 moles of water in this molecule then multiply the RMM of H2O by 6 = 108.0924

Finally, divide the total H2O RMM by the total molecule RMM and multiply by 100 to get a percentage:
(108.0925 / 237.96) x 100 = 45.42%

7 0

3 years ago

How many liters of 1.0 M HCl do you need to neutralize 2.0 L of 3.0 M NaOH? How many liters of 1.0 M HCl do you need to neutrali

Kruka [31]

Answer:

For 1: The volume of HCl required is 6 L.

For 2: The volume of HCl required is 9 L.

For 3: The volume of sulfuric acid required is 4.5 L.

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$ ......(1)

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base

For 1:

We are given:

$n_1=1\\M_1=1M\\V_1=?L\\n_2=1\\M_2=3.0M\\V_2=2.0L$

Putting values in equation 1, we get:

$1\times 1\times V_1=1\times 3\times 2\\\\V_1=6L$

Hence, the volume of HCl required is 6 L.

For 2:

We are given:

$n_1=1\\M_1=1M\\V_1=?L\\n_2=2\\M_2=3.0M\\V_2=1.5L$

Putting values in equation 1, we get:

$1\times 1\times V_1=2\times 3.0\times 1.5\\\\V_1=9L$

Hence, the volume of HCl required is 9 L.

For 3:

To calculate the volume of acid, we use the equation:

$N_1V_1=N_2V_2$

where,

$N_1\text{ and }V_1$ are the normality and volume of acid

$N_2\text{ and }V_2$ are the normality and volume of base

We are given:

$N_1=1.0N\\V_1=?L\\N_2=3.0N\\V_2=1.5L$

Putting values in above equation, we get:

$1.0\times V_1=3.0\times 1.5\\\\V_1=4.5L$

Hence, the volume of sulfuric acid required is 4.5 L.

8 0

3 years ago

write a balanced net ionic equation for the following reaction: BaCl2(aq) + H2SO4 (aq) -- BaSO4(s) + HCl (aq)

Fudgin [204]

The balanced net equation for

BaCl2 (aq) + H2SO4(aq) → BaSO4(s) + HCl (aq) is

Ba^2+(aq) +SO4^2- → BaSO4 (s)

Explanation

Ionic equation is a chemical equation in which electrolytes in aqueous solution are written as dissociated ions.

ionic equation is written using the below steps

Step 1: write a balanced molecular equation

BaCl2 (aq) +H2SO4 (aq)→ BaSO4(s) +2HCl (aq)

Step 2: Break all soluble electrolytes in to ions

= Ba^2+ (aq) + 2Cl^-(aq) + 2H^+(aq) + SO4^2-(aq)→ BaSO4(s) + 2H^+(aq) +2Cl^- (aq)

step 3: cancel the spectator ions in both side of equation ( ions which do not take place in the reaction)

 = 2Cl^- and 2H^+ ions

Step 4: write the final net equation

 Ba^2+(aq) + SO4^2-(aq)→ BaSO4(s)

3 0

3 years ago

Read 2 more answers

A deck of cards has dimensions 8.9cm x 5.72cm x 1.82 cm. What is the volume of the deck in cubic centimeters?

arsen [322]

Answer:

92.65256 cm^3

Explanation:

To find this, we can simply multiply all three dimensions to get the answer in cubic centimeters, and we get the answer above. If you want to be more specific, we can go by the sigfig rule and the answer would be rounded to 93 cm^3.

5 0

3 years ago

Calculate the electrical energy per gram of anode material for the following reaction at 298 K:

antiseptic1488 [7]

The answer is:

E per gram = 0.45 V

The explanation:

when MnO2 is the substance who oxidized here so, the oxidizing agent and the anode here is Li.

and when the molar mass of Li is = 7 g/mol

and in our reaction equation we have 1 mole of Li will give 3.15 V of the electrical energy

that means that :

7 g of Li gives → 3.15 V

So 1 g of Li will give→ ???

∴ The E per gram = 3.15 V / 7 g of Li

= 0.45 V

6 0

4 years ago

Read 2 more answers