Answer:
4' x 2' x 1'
Step-by-step explanation:
Collins' cube has a volume of that is the length of any side, x, cubed: Vol = x^3. Since his box has 8^3, we can say that x = 2. <u>[2^3 = 8]</u>
Amil's box has one side that is 2x. That side would be 2*2 = 4 feet. His volume is also 8 ft^3. Amil's box also has a volume of 8 ft^3.
His box dimensions are therefore: (4)(X)(Y) = 8 ft^3 , where X and Y are whole-number dimensions for the other 2 dimensions of his box.
(4)(X)(Y) = 8 ft^3
X*Y = 2
The only combination of whole numbers for which this this would work is 1 and 2.
Amil's box is 4' x 2' x 1' or 8 ft^3
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Answer:
64
Step-by-step explanation:
Find the area of both triangles inside the bigger triangle and add them together.
Use the Pythagorean theorem to find the missing length of the leg in the smallest triangle:
a² + b² = c²
8² + b² = 10²
64 + b² = 100
36 = b²
6 = b
Calculate the area of the smaller triangle:
1/2(<em>b</em>x<em>h</em>)
1/2(6 x 8)
1/2(48)
24
Calculate the area of the bigger triangle:
<em>We know that the longer leg is 10 units because we were able to subtract the length of the smaller triangle's leg from 16.</em>
1/2(<em>b</em>x<em>h</em>)
1/2(10 x 8)
1/2(80)
40
Add both areas to find the area of the largest triangle:
40 + 24 = 64
Answer:
29 ; 37
Step-by-step explanation:
The figure is composed by a square, a rectangle, and a right triangle
The perimeter of the square is 6 units
The perimeter of the rectangle is 10 units
The triangle is composed by a side of 6 units and a side of 5 units
The third side can be find with the Pythagorean theorem
= 7,81025
The total perimeter is
6 + 10 + 5 + 7,81025 = 28,81025 = 29
Area of the square = 2^2 = 4 square units
Area of the rectangle = 6 x 3 = 18 square units
Area of the triangle = (5 x 6)/2 = 15 square units
Total area = 4 + 18 + 15 = 37 square units
54/2 or 27 should be the answer
