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sattari [20]
3 years ago
11

Complete the recursive formula of the arithmetic sequence 12, 10, 8, 6,...12,10,8,6,...12, comma, 10, comma, 8, comma, 6, comma,

point, point, point.
b(1)=b(1)=b, left parenthesis, 1, right parenthesis, equals

b(n)=b(n-1)+b(n)=b(n−1)+b, left parenthesis, n, right parenthesis, equals, b, left parenthesis, n, minus, 1, right parenthesis, plus
Mathematics
2 answers:
pogonyaev3 years ago
4 0

Complete Question:

Complete the recursive formula of the arithmetic sequence 12, 10, 8, 6, ....

b_1 = [\ ]

b_n = b_{n - 1} + [\ ]

Answer:

b_1 = 12

b_n = b_{n-1} - 2

Step-by-step explanation:

Required

Complete:

b_1 = [\ ]

b_n = b_{n - 1} + [\ ]

From the question, the first term is 12.

So:

b_1 = 12

Solving further:

b_2 = 10 = 12 - 2 = b_1 - 2

b_3 = 8 = 10 - 2 = b_2 - 2

b_4 = 6 = 8 - 2 = b_3 - 2

Following the above sequence:

b_n can then be calculated as

b_n = b_{n-1} - 2

iren [92.7K]3 years ago
4 0

Answer:

12

-2

Step-by-step explanation:

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What two numbers have a difference of 5 and a product of 3.36
iris [78.8K]
X-y=5
xy=3.36
add y to both sides on first
x=5+y
sub that in other eqation
(5+y)y=3.36
expand
y^2+5y=3.36
minus 3.36 both sides
y^2+5y-3.36=0
use quadratic formula


for
ay^2+by+c=0
y= \frac{-b+/- \sqrt{b^2-4ac} }{2a}
for 1y^2+5y-3.36
y= \frac{-5+/- \sqrt{5^2-4(1)(-3.36)} }{2(1)}
y= \frac{-5+/- \sqrt{25+13.44} }{2}
y= \frac{-5+/- \sqrt{38.44} }{2}
y= \frac{-5+/- 6.2}{2}
y=-2.5+/-3.1
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sub back

x=y+5
so
x=10.6 or 5.6


the numbers are either 10.6 and 5.6 or 0.6 and 5.6
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