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Lerok [7]
3 years ago
15

If 8,a,b,27 are in geometric sequence, find the value of a and b.​

Mathematics
1 answer:
wel3 years ago
3 0

Answer:

a = 12 and b = 18

Step-by-step explanation:

Given that,

8,a,b,27 are in geometric sequence.

For a GP, the nth term is given by :

a_n=ar^{n-1}

Put n = 4

a_4=ar^{4-1}\\\\a_4=ar^3\\\\27=8\times r^3\\\\r^3=\dfrac{27}{8}\\\\r=\dfrac{3}{2}=1.5

Put n = 2,

a_2=ar^{2-1}\\\\a=ar\\\\a=8\times 1.5\\\\a=12

Put n = 3

a_3=ar^2\\\\=8\times 1.5^2\\\\b =18

So, the values of a and b is 12 and 18 respectively.

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Note there is a common difference d between consecutive terms of the sequence, that is

d = - 7 - (- 9) = - 5 - (- 7) = - 7 + 9 = - 5 + 7 = 2

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