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4 years ago

draw a strip diagram to Model 5 hours 8 minutes minus 3 hours 12 minutes write an equation to find the difference

1 answer:

8 0

You can convert everything in minutes once you've solved it you turn it back to hours and minutes....5hrs and 8min= 308min....3hrs 12min=192min....308-192=116.....116 is 1hr and 56min

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Simplify this expression: cos theta/ tan theta cot theta

Dmitry_Shevchenko [17]

Q: $\frac{cos\theta}{tan\theta.cot\theta}=?$

A:

$\frac{cos\theta}{tan\theta.cot\theta}=cos\theta$

because... $tan\theta.cot\theta=1$
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Q: $\frac{cos\theta}{tan\theta}.cot\theta=?$

A:

$\frac{cos\theta}{tan\theta}.cot\theta&= \\ \\ \frac{cos\theta}{\frac{sin\theta}{cos\theta}}.\frac{cos\theta}{sin\theta}&= \\ \\ \frac{cos^2\theta}{sin\theta}}.\frac{cos\theta}{sin\theta}&= \\ \\ \frac{cos^3\theta}{sin^2\theta}}&= cos^3\theta.cosec^2\theta$

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4 years ago

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tamaranim1 [39]

A country's income distribution is the distribution of total GDP among the total population

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3 years ago

Which graph has a rate of change equal to 1-3 in the interval between 0 and 3 on the x-axis

inessss [21]

Answer:-2

Step-by-step explanation:

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3 years ago

Maria needs 3.87 feet of string to use as a border for her poster. Maria finds two pieces of string one that is 2.5 feet long an

lukranit [14]

Answer:x = 4.25 - 3.87 x = 0.38 feet

Step-by-step explanation::Find out the how much string will Mellisa have left over .To proveLet us assume that the string will Mellisa have left over be x .As givenMelissa needs 3.87 feet of string to use as a border for her poster.Melissa finds a piece of string that is 4.25 feet long.Than the equation is write in the form. Therefore the string will Mellisa have left over be 0.38 feet .

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3 years ago

Find the general solution to the differential equation modeling how a person learns:

Luda [366]

Here we want to solve differential equations, we will see that the general solution is:

$y = A*e^{-t} + 100$

We want to solve the differential equation:

$\frac{dy}{dt} = 100 - y$

From this is pretty clear that y is an exponential function, with an exponent of -1*t.

We can write it generally as:

$y = A*e^{-t} + B\\\\\frac{dy}{dt} = -A*e^{-t}$

Then if we set B = 100 we get:

$y = A*e^{-t} + 100\\\\\frac{dy}{dt} = -A*e^{-t} \\\\\frac{dy}{dt} = -A*e^{-t} - 100 + 100 = -y + 100$

So we just found the general form of the function.

Now we have two cases:

A) y(0) = 35

$y(0) = A*e^{-0} + 100 = 35\\= A + 100 = 35\\\\A = 35 - 100 = -65$

In this case, the function is:

$y = -65*e^{-t} + 100$

B) y(0) = 125

$125 = A*e^0 + 100\\\\\125 - 100 = A\\\\25 = A$

In this case, the function is:

$y = 25*e^{-t} + 100$

Now we want to see which one of the two can represent how a person learns. Just look at the graph below:

The green line is the one for y(0) = 35, and the blue one is for y(0) = 125.

Notice that for small values of t, the blue function is really large, thus it can't really model how a person learns (is larger for smaller values of t than for larger values).

So y(0) = 35 represents better how a person can learn (but not exactly, because you can see that it eventually becomes almost constant, which is something that really does not happen) so the correct option is D: none of the above.

If you want to learn more, you can read:

brainly.com/question/353770

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3 years ago