All three of them do exist on the line y = 2.5x + 4
In order to find the answer to this question, start by finding the line for two points. For this example, we'll use A and C.
First we need to find the slope.
(y1 - y2)/(x1 - x2)
(9 - -1)/(2 - -2)
(9 + 1)/(2 + 2)
10/4
2.5
Now using slope intercept form and point A, we can determine the intercept of that line as well.
y = mx + b
-1 = 2.5(-2) + b
-1 = -5 + b
4 = b
So now we know A and C form the line y = 2.5x + 4. We can then check if B fits that line.
y = 2.5x + 4
4 = 2.5(0) + 4
4 = 0 + 4
4 = 4 (TRUE)
Therefore, it also falls on that line.
Answer:
you are right............
Answer:
Step-by-step explanation:
The points on the straight line are (P, 0) and (0, R).
The slope would be
And 
, because the y-intercept is at (0, R).
So, the equation of this line would be
Where we multiply the equation by 
Therefore, the equation that represents this line is
<h2>
So, the right answer is B.</h2>
894 mi^2
as 24 x 37.25 = 894
Answer:
D
Step-by-step explanation:
∠ 6 is formed by the 2 lines that intersect at D
then the vertex of ∠ 6 is D
