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GREYUIT [131]
3 years ago
14

The scatter plot shows the number of days that several homes have been for sale co.pared to the number of times the house has be

en viewed.
Mathematics
2 answers:
Mamont248 [21]3 years ago
7 0

Answer:

It would be the scattered pot - how many

Step-by-step explanation:

Phoenix [80]3 years ago
7 0
Two triangles are similar. Triangle ABC has side lengths of AB = 10, BC = 6, CA = 7. Triangle XYZ has a side length of XY = 8. Find YZ.
You might be interested in
3t hreater or less than 3,000 lb
pochemuha
3 tons would be greater than 3,000 pounds

1 ton= 2,000 pounds
3 tons=6,000 pounds
7 0
4 years ago
Select True or False.
Lyrx [107]

The expression is False the correct answer would be: −x+12

3 0
3 years ago
Read 2 more answers
⚠️‼️ HELP PLEASE GIVING POINTS ​
Nezavi [6.7K]

Answer:

CBD = 63 degrees

Step-by-step explanation:

To find CBD, we must first find the value of x. To do so, we use this equation since CBD and ABC equal 96 degrees:

(6x+27) + (7x-9) = 96
13x+18 = 96
13x+18-18 = 96-18
13x = 78
13x/13 = 78/13
x = 6

Now that we know the value of x, we factor it in to CBD to find its true value:

6x+27
6(6)+27
36+27
= 63 degrees

To check if this answer is correct, we can also find the value of ABC and see if the two values equal 96:

7x-9
7(6)-9
42-9
= 33 degrees

63 + 33 = 96

The answer is correct. CBD = 63 degrees and ABC = 33 degrees.

8 0
2 years ago
A Niffler is a magical creature who loves to collect shiny objects and store them in their pouch, much like a kangaroo. The amou
Fudgin [204]

Answer:

Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

Step-by-step explanation:

We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.

Let X = <u><em>amount a Niffler can hold in their pouch</em></u>

So, X ~ Normal(\mu=25,\sigma^{2} =6.8^{2})

The z score probability distribution for normal distribution is given by;

                                Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 25 pounds

            \sigma = standard deviation = 6.8 pounds

Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)

  P(X > 32 pounds) = P( \frac{X-\mu}{\sigma} > \frac{32-25}{6.8} ) = P(Z > 1.03) = 1 - P(Z \leq 1.03)

                                                             = 1 - 0.8485 = 0.1515

<em>The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.</em>

<em />

Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

4 0
3 years ago
There is 267 students and 21 adults going on a school trip.An equal number of people will ride on each bus .If there 9 buses,how
Fittoniya [83]

Answer:

32

Step-by-step explanation:

267+21=288

288/9=32

7 0
3 years ago
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