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inysia [295]
3 years ago
12

Help me solve this please!!

Mathematics
2 answers:
AVprozaik [17]3 years ago
8 0

Answer:

Q 1. 8 yds Q2. 12 ft :)

Step-by-step explanation:

I got this right on my test so it should be the same.

astra-53 [7]3 years ago
4 0

Answer:

y = 2 yd

Step-by-step explanation:

2y = 2 × 24 /12 = 4 yd

y = 2 yd

second answer dont know sorry because I dont know about trapezoid. I hope someone will help you with that

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The ratio of boys to girls in Ms. smith’s class is 3 to 4. If there are 12 boys, how many girls are there?
Lorico [155]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ There will be 16 girls.

The relationship is x4. If we multiply 3 x 4, we get 12. What we do to one number we do to the other so 4 x 4 = 16.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

4 0
3 years ago
Let f(t) give the number of liters of fuel oil burned in t days, and w(r) the liters burned in r weeks. Find a formula for w by
viktelen [127]

Answer:

7 f(t)

Step-by-step explanation:

So, our f(t) is the number of liters burned in t days. If t is 1, f(t)=f(1) and so on for every t.

w(r) id the number of liters in r weeks. This is, in one week there are w(1) liters burned.

As in one week there are 7 days, we can replace the r, that is a week, by something that represents 7 days. As 1 day is represented by t, one week can be 7t (in other words r = 7t). So, we have that the liters burned in one week are:

w(r) = w[7f(t)]

So, we represented the liters in one week by it measure of days.

So, we can post that the number of liters burned in 7 days is the same as the number of liters burned 1 day multiplied by 7 times. So:

w (r) = w[7 f(t)] = 7 f(t)

Here we hace the w function represented in terms of t instead of r.

3 0
3 years ago
I am confused on how to do this? please help!
IceJOKER [234]
You would take random numbers preferable smaller ones such as -1,0,1,2
You would put those in the place of x
Then you would square the value of x. After that you subtract 4. Whatever you come out with is your y value. Then you put the x value on the x axis and from that point count up or down to the number you need on the y axis. Together that would be your point
6 0
2 years ago
Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10
natka813 [3]

ANSWER

( \frac{2}{3} , \frac{1}{5} )

EXPLANATION

The first equation is

\frac{1}{2} x -  \frac{3}{4} y =  \frac{11}{60} ...(1)

The second equation is

\frac{2}{5} x  +  \frac{1}{6} y =  \frac{3}{10} ...(2)

We want to eliminate y, so we multiply the first equation by

\frac{4}{5}

\frac{4}{5}  \times \frac{1}{2} x - \frac{4}{5}    \times \frac{3}{4} y =  \frac{11}{60}  \times  \frac{4}{5}

\frac{2}{5} x - \frac{3}{5} y =  \frac{11}{75} ...(3)

We now subtract equation (3) from (2)

(\frac{2}{3} x  -  \frac{2}{3} x )+ ( \frac{1}{6} y -  -  \frac{3}{5}y ) =(  \frac{3}{10}  -  \frac{11}{75} )

\frac{1}{6} y  +  \frac{3}{5}y  =\frac{3}{10}  -  \frac{11}{75}

\frac{23}{30}y =  \frac{23}{150}

Multiply both sides by

\frac{30}{23}

\implies \:  \frac{30}{23} \times  \frac{23}{30}y=  \frac{23}{150}  \times  \frac{30}{23}

\implies \: y =  \frac{1}{5}

Substitute into the first equation to solve for x .

\frac{1}{2} x -  \frac{3}{4}  \times \frac{1}{5} =  \frac{11}{60}

Multiply to obtain

\frac{1}{2} x -  \frac{3}{20} =  \frac{11}{60}

\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}

\frac{1}{2} x = \frac{1}{3}

Multiply both sides by 2.

2 \times \frac{1}{2} x =2 \times  \frac{1}{3}

x = \frac{2}{3}

The solution is

( \frac{2}{3} , \frac{1}{5} )

5 0
2 years ago
Read 2 more answers
Compute the difference quotient StartFraction f left parenthesis x plus h right parenthesis minus f left parenthesis x right par
kenny6666 [7]

Answer:

\dfrac{f(x+h) - f(x)}{h}=-8x-4h-3

Step-by-step explanation:

f(x)=-4x^2-3x-4

f(x+h)=-4(x+h)^2-3(x+h)-4

f(x+h)=-4(x^2+2xh+h^2)-3(x+h)−4

f(x+h)=-4x^2-8xh-4h^2-3x-3h-4

f(x+h) - f(x)=-4x^2-8xh-4h^2-3x-3h-4-(-4x2-3x-4)

f(x+h) - f(x)=-4x^2-8xh-4h^2-3x-3h-4+4x2+3x+4

f(x+h) - f(x)=-8xh-4h^2-3h

f(x+h) - f(x)=h(-8x-4h-3)

\dfrac{f(x+h) - f(x)}{h}=\dfrac{h(-8x-4h-3)}{h}

\dfrac{f(x+h) - f(x)}{h}=-8x-4h-3

7 0
3 years ago
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