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nikitadnepr [17]
3 years ago
11

BRAINLIEST 20PTSSSS

Mathematics
2 answers:
Licemer1 [7]3 years ago
4 0

Answer:

A,D,E

Step-by-step explanation:

antiseptic1488 [7]3 years ago
3 0

Answer:

A, C and E I think. Hope this helps! <3

Step-by-step explanation:

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What is the quotient of 21.06 and 9​
bekas [8.4K]

Answer:

21.06÷9 = 2 and 36 left over

Step-by-step explanation:

5 0
3 years ago
Two friends left school at the same time and drove in opposite directions. One friend averages 40 miles per hour and the other f
EastWind [94]
The two friends will be 150 miles apart, when the sum of the distances covered by the them is 150 miles.

distance = speed x time.
Let the time covered when they are 150 miles apart be x, then:
40x + 35x = 150
75x = 150
x = 150/75 = 2.

Therefore, the two friends will be 150 miles apart in 2 hours.
3 0
4 years ago
Find the length to the nearest centimeter of the diagonal of a square 30 cm. on a side
tiny-mole [99]

Answer:

42 cm.

Step-by-step explanation:

Please find the attachment.

Let x be the length of diagonal of the square.

We have been given that length of each side of a square is 30 cm. We are asked to find the length of the diagonal of square to the nearest centimeter.

We can see from our diagram that triangle AC is the diagonal of our square.

Since all the interior angles of a square are right angles or equal to 90 degrees, so we will use Pythagoras theorem to find the length of diagonal.

AC^2=AD^2+DC^2  

Upon substituting our given values in above formula we will get,

x^2=(30\text{ cm})^2+(30\text{ cm})^2

x^2=900\text{ cm}^2+900\text{ cm}^2

x^2=1800\text{ cm}^2

Let us take square root of both sides of our equation.

x=\sqrt{1800\text{ cm}^2}

x=42.4264\text{ cm}\approx 42\text{ cm}

Therefore, the length of diagonal of our given square is 42 cm.

8 0
3 years ago
PLEASE HELP ME!! I WILL GIVE U BRAINLIEST
Anvisha [2.4K]

Answer:

Step-by-step explanation:the anwser is the middle one

5 0
3 years ago
(Show your working) I uploaded the question
svlad2 [7]

x^2 = the first integer

(x - 1)^2 = the second integer.

x^2 - (x - 1)^2 = ?

First, let's plug a number into our equation for x.

(2)^2 - (2 - 1)^2 = ?

4 - (1)^2 = ?

4 - 1 = 3

As we can see the difference is odd but it's also the sum of the two consecutive integers.

2 + 1 = 3.

This works for all numbers. Let's plug another number into our equation for x.

(4)^2 - (4 - 1)^2 = ?

16 - (3)^2 = ?

16 - 9 = 7

4 + 3 = 7

Try any number and it will always be odd.

4 0
3 years ago
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