2. a) absolute values for the slopes
y = mx + c
3/4, 9,-11, -1 = 3/4, 9,11, 1
the higher the slope, the steeper the graph. 11 is high,
y = -11x - 5
b) 1/4,3,-3/4,-8 = 1/4,3,3/4,8
smaller value is 3/4
the least steep graph will be in,
y = -3/4x + 7
c) 6,2,1, 1/2
1/2 is the smallest value.
y = 1/2x + 6
d) It would be less steep.
e) It would be shifted down.
f) y = -8x - 3
g) y = 1/4x + 9
h) y = 3x - 1
i) y = -5x - 10
Answer:
0.00137174211 :,)
Step-by-step explanation:
Answer:
C. (-1, 0)
Step-by-step explanation:
(You don't need a picture to figure this out...it's simple algebraic manipulation.)
We could start off by rewriting the equation for the parabola with the negative on the other side, which tells us then that the parabola opens downward:

Dividing both sides by -1 doesn't change anything. Because this parabola opens downward, the focus is p units below the vertex at the same x-coordinate. The vertex can be found from the equation to be (-1, 2). The standard form of a parabola of this type is

where is the number of units between the vertex and the focus. Our equation to find p is:
4p = 8 so p = 2.
That means that the focus is 2 units below the vertex at the x coordinate of -1. Moving 2 units down from the y coordinate of 2 leaves us at a y coordinate of 0. Therefore, the coordinates of the focus have to be (-1, 0)
Answer:
It is C.
Step-by-step explanation:
You divided 6.57 by 3
and 3 by 3
3 by 3 = 1
6.57 = 2.19
3 so for every 1 pound it costs $2.19
Answer:
15 units
Step-by-step explanation:
The distance between two points can be found using the following formula:

Given points:
(-7, 5) and (2, -7)
<u>where:</u>
- x₁ = -7
- x₂ = 2
- y₁ = 5
- y₂ = -7
Substitute these points into the formula and simplify:
![\sf d=\sqrt{(2-(-7))^2+((-7)-5)^2} \ \textsf{[simplify the radicand]}\\\\ d=\sqrt{(2+7)^2+(-12)^2} \ \textsf{[simplify]}\\\\d=\sqrt{(9)^2+(-12)^2} \ \textsf{[evaluate the power]}\\\\d=\sqrt{81+144} \ \textsf{[add]}\\\\d=\sqrt{225}\ \textsf{[simplify]}\\\\d=15](https://tex.z-dn.net/?f=%5Csf%20d%3D%5Csqrt%7B%282-%28-7%29%29%5E2%2B%28%28-7%29-5%29%5E2%7D%20%5C%20%5Ctextsf%7B%5Bsimplify%20the%20radicand%5D%7D%5C%5C%5C%5C%20d%3D%5Csqrt%7B%282%2B7%29%5E2%2B%28-12%29%5E2%7D%20%5C%20%5Ctextsf%7B%5Bsimplify%5D%7D%5C%5C%5C%5Cd%3D%5Csqrt%7B%289%29%5E2%2B%28-12%29%5E2%7D%20%5C%20%5Ctextsf%7B%5Bevaluate%20the%20power%5D%7D%5C%5C%5C%5Cd%3D%5Csqrt%7B81%2B144%7D%20%5C%20%5Ctextsf%7B%5Badd%5D%7D%5C%5C%5C%5Cd%3D%5Csqrt%7B225%7D%5C%20%5Ctextsf%7B%5Bsimplify%5D%7D%5C%5C%5C%5Cd%3D15)
The distance between the two points is 15 units.
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