Answer:
Step-by-step explanation:
From the information given, you can write the following equations:
x+y=300 (1)
5x+8y=300*7
5x+8y=2100(2)
First, you can isolate x in (1):
x=300-y (3)
Now, you can replace (3) in (2):
5(300-y)+8y=2100
1500-5y+8y=2100
3y=2100-1500
y=600/3
y=200
Then, you can replace the value of y in (3) to find x:
x=300-200
x=100
According to this, the answer is that he should use 100 pounds of dried pineapple and 200 pounds of dried apricots.
Hey there!
First, divide both sides by 12
-12(k+4)/-12= 60/-12 and you would getk+4=5
Now subtract 4 from both sides
k+4-4= 5-4
k=-9
What is the interquartile range for the data set 4,7,7,3,5,2,6,7,9 the answers are 3.5, 5.6, 7,9
polet [3.4K]
5.6 is the answer for your question
Answer:
Step-by-step explanation:
The function used to represent the height of a punted football can be modeled as
f(x) = -.0079x² + 1.8x + 1.5
Where f(x) is the height in feet, and x is the horizontal distance, also in feet.
a) when the ball was punted, x = 0, therefore, the height of the punted ball would be
f(x) = -.0079(0)² + 1.8(0) + 1.5
f(x) = 1.5 feet
The height is 1.5 feet
b) The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height reached by the punted ball.
The vertex of the parabola is calculated as follows,
Vertex = -b/2a
From the equation,
a = - 0.0079
b = 1.8
Vertex = - - 1.8/0.0079 = 227.84 feet
So the maximum height of the punt is 227.84 feet
Answer:
<u>A</u>
Step-by-step explanation:
