What is the sum of the first 20 terms of a finite geometric series where a1 =3 and r = 3/2
1 answer:
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Answer:
19 years
Step-by-step explanation:
The attached spreadsheet shows the balance will be zero at the beginning of year 19, when the last $10,423.27 is withdrawn from the account.
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One could argue that the "nearest year" is year 18, when the balance after the withdrawal is less than $10,000.
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In the attached spreadsheet, the ending balance is 1.082 times the beginning balance (after deposits and withdrawals), which is the ending balance of the year before (after deposits).
In year 1 the beginning balance has 100,000 added. In year 2, the ending balance has 55,000 added. In year 4 and every year after, the beginning balance as 20,000 subtracted.
Answer:
x = ± , x = ± i
Step-by-step explanation:
f(x) = - x² - 2
to find the zeros , equate f(x) to zero , that is
- x² - 2 = 0
using the substitution u = x² , then
u² - u - 2 = 0 ← in standard form
(u - 2)(u + 1) = 0 ← in factored form
equate each factor to zero and solve for u
u - 2 = 0 ⇒ u = 2
u + 1 = 0 ⇒ u = - 1
convert u back into terms of x
x² = 2 ( take square root of both sides )
x = ±
x² = - 1 ( take square root of both sides )
x = ± = ± i