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balu736 [363]
2 years ago
12

Select the correct answer.

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
4 0

Answer:

\log_{3} ({5\sqrt{x}} * y ) = \log_{3}({5) + \log_{3}(\sqrt{x}) +\log_{3}( y )

Step-by-step explanation:

Given

\log_{3} ({5\sqrt{x}} * y )

Required

Write as sum or difference

Using addition law of logarithm, the equation becomes:

\log_{3} ({5\sqrt{x}} * y ) = \log_{3}({5\sqrt{x}) +\log_{3}( y )

Expand

\log_{3} ({5\sqrt{x}} * y ) = \log_{3}({5 * \sqrt{x}) +\log_{3}( y )

Apply addition law

\log_{3} ({5\sqrt{x}} * y ) = \log_{3}({5) + \log_{3}(\sqrt{x}) +\log_{3}( y )

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What is the area of triangle EDF?
Ann [662]

Answer:

4.5

Step-by-step explanation:

∠BAC ~ ∠EDF means that the triangles are similar. So the legs of the triangle share the same proportions, even if the sizes are different.

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The answer can be found with the knowledge that the area of a triangle is half of the height * width. You know the width of ∠BAC is 4, and the area is 8, so 16 (the area doubled) / 4 is the height. The width and height of ∠BAC are the same, and since the proportions are also the same, the width and height of ∠EDF are both 3. So the area is the width (3) times the height (3) divided by 2.

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Step-by-step explanation:

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