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balu736 [363]
3 years ago
12

Select the correct answer.

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
4 0

Answer:

\log_{3} ({5\sqrt{x}} * y ) = \log_{3}({5) + \log_{3}(\sqrt{x}) +\log_{3}( y )

Step-by-step explanation:

Given

\log_{3} ({5\sqrt{x}} * y )

Required

Write as sum or difference

Using addition law of logarithm, the equation becomes:

\log_{3} ({5\sqrt{x}} * y ) = \log_{3}({5\sqrt{x}) +\log_{3}( y )

Expand

\log_{3} ({5\sqrt{x}} * y ) = \log_{3}({5 * \sqrt{x}) +\log_{3}( y )

Apply addition law

\log_{3} ({5\sqrt{x}} * y ) = \log_{3}({5) + \log_{3}(\sqrt{x}) +\log_{3}( y )

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Simplify the expression<br> (-1-3i)(-6-i)
Ivan
(-1-3i)(-6-i)
=6+i+18i+3i^2
=3i^2+19i+6. Hope it help!
7 0
3 years ago
Alex runs on the track at school each weekday morning. If he runs 5.9 miles each day, about how much does he run every month?
Lisa [10]
Now, since we know that 5.9 is the amount of miles per day, we need to determine how many miles per month.

Usually, there are 20 days...because of no weekdays

Multiply.

5.9 * 20 = 118

Final answer:- He runs 118 miles per month. 

3 0
4 years ago
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Do we go back 2 ppaces or go forward 2 places when making percenta into decimals
xxMikexx [17]
Move the decimal to the left 2 spaces.  90% would .90.  74% would be .74.  134% would be 1.34  Got it?  It' always the same no matter the percent.  2 spaces to the left.
7 0
3 years ago
What is the actual height of the building shown in the model?
julsineya [31]

Answer:

The actual height is 150ft

Step-by-step explanation:

Given

Width : Height = 2cm : 5cm

Actual\ width = 60ft

Required

Determine the actual height

Substitute 60ft for width in: Width : Height = 2cm : 5cm

60ft:Height =2cm:5cm

Express as fraction

\frac{60ft}{Height} =\frac{2cm}{5cm}

\frac{60ft}{Height} =\frac{2}{5}

Make height the subject

Height = \frac{5}{2} * 60ft

Height = 5 * 30ft

Height = 150ft

7 0
3 years ago
Read 2 more answers
What is the sum or difference?
dlinn [17]
1. Ans: Option (B) -6x^4

Explanation:
Given: 2x^4 - 8x^4
Take the common out:
=> x^4(2 - 8)

Hence: => [tex]-6x^4[/tex] (Option B)

2. Ans: Option (D) -3y^5

Explanation:
Given: 6y^5 - 9y^5
Take the common term(s) out:
=> y^5(6-9)

Hence: => -3y^5 (Option D)

3. Ans: Option (B) 9x^2 - 12x + 6<span> quadratic trinomial 

Explanation:
</span>Given: 6 - 12x + 13x^2 - 4x^2

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> 
13x^2 - 4x^2 - 12x + 6
=> 9x^2 - 12x + 6 (Option B)

4. Ans: Option (C) 7.3x^2 + 0.8x + 1.3

Explanation:
In order to find the total number of C<span>ommon and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

</span>Common guppies: 3.1x^2 +6.0x + 0.3<span>
Endler's guppies:   </span>4.2x^2 - 5.2x + 1.0
(add both)
-----------------------------------------------------------------
Total number:          7.3x^2 +0.8x + 1.3
-----------------------------------------------------------------
Hence the ans is Option(C) 7.3x^2 + 0.8x + 1.3

5. Ans: Option (D) 2x^2(133 - 18 \pi )

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = 266x^2

Now the area of the circular fountain:
Area of the Circular Fountain = \pi r^2
Since, r=6x
Therefore,
Area of the Circular Fountain = \pi (6x)^2 = 36 \pi x^2

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = 266x^2 - 36 \pi x^2
=> Final area of the Yard = 2x^2(133 - 18 \pi) (Option D)

6. Ans: Option (A) 56x^2

Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = 60x^2

Now the area of the stadium:
Area of the stadium = 1x * 4x = 4x^2

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= 60x^2 - 4x^2
=> Final area of the lot = 56x^2 (Option A)

-i
4 0
3 years ago
Read 2 more answers
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