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zloy xaker [14]

3 years ago

14

Can someone help me with these 2 problems please

1 answer:

mel-nik [20]3 years ago

6 0

Don’t go to that link it’s bad they trying to scam you

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professor190 [17]

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Answer:

$\huge\boxed{\tan x=\dfrac{\sin x}{\cos x}}$

Step-by-step explanation:

$\tan x\cos x=\sin x\\\\\tan x=\dfrac{\sin x}{\cos x}\\\\\text{Therefore}\\\\\tan x\cos x=\dfrac{\sin x}{\cos x}\cdot\cos x\qquad\text{cancel}\ \cos x\\\\\tan x\cos x=\sin x\\\\\text{For}\ x\neq\dfrac{\pi}{2}+k\pi},\ k\in\mathbb{Z}$

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melisa1 [442]

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2 years ago

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stich3 [128]

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