Can someone help me with these 2 problems please

Simplify your answer as much as possible

loris [4]

9514 1404 393

Answer:

-4u^2/y+(5/2)y^3u^2

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

(a^b)/(a^c) = a^(b-c)

__

$(8y^2u^7-5y^6u^7)\div(-2y^3u^5)=\dfrac{8y^2u^7-5y^6u^7}{-2y^3u^5}\\\\=-4y^{2-3}u^{7-5}+\dfrac{5}{2}y^{6-3}u^{7-5}=\boxed{\dfrac{-4u^2}{y}+\dfrac{5}{2}y^3u^2}$

7 0

2 years ago

Help please i need answers fast if you help or try to help tysm *hearts*

Tanzania [10]

Answer:

C. 3rd one Fraction 10/24

Step-by-step explanation:

3/4 - 2/6 = 0.41 or = 10/24 or it could be equal to 5/12 are 10/24, 15/36, 20/48 and 25/60 or as Decimal 0.41

Step-by-step explanation:

Hope This Helped

7 0

2 years ago

Which size bag of cat food shown in table has the lowest unit price?

motikmotik

The 40 oz and $8.00 i think

7 0

3 years ago

mr. Roberts is going shopping. he has a budget of $150.00. he will buy either a painting or a lamp. if he spends 80% of his mone

Elenna [48]

Mr. Roberts will spend $132 on a painting

3 0

3 years ago

Unit 7 polygons & quadrilaterals homework 3: rectangles Gina Wilson answer key

Irina-Kira [14]

Answer:

In the image attached you can find the Unit 7 homework.

We need to findt he missing measures of each figure.

Notice that the first figure is a rectangle, which means opposite sides are congruent so,

VY = 19

WX = 19

YX = 31

VW = 31

To find the diagonals we need to use Pythagorean's Theorem, where the diagonals are hypothenuses.

$VX^{2}=19^{2}+31^{2}\\ VX=\sqrt{361+961}=\sqrt{1322} \\VX \approx 36.36$

Also, $YW \approx 36.36$ , beacuse rectangles have congruent diagonals, which intercect equally.

That means, $ZX = \frac{VX}{2} \approx \frac{36.36}{2}\approx 18.18$

Figure number two is also a rectangle.

If GH = 14, that means diagonal GE = 28, because diagonals intersect in equal parts.

Now, GF = 11, because rectangles have opposite sides congruent.

DF = 28, because in a reactangle, diagonals are congruent.

HF = 14, because its half of a diagonal.

To find side DG, we need to use Pythagorean's Theorem, where GE is hypothenuse

$GE ^{2}=11^{2}+DG^{2}\\28^{2}-11^{2}=DG^{2}\\DG=\sqrt{784-121}=\sqrt{663}\\ DG \approx 25.75$

This figure is also a rectangle, which means all four interior angles are right, that is, equal to 90°, which means angle 11 and the 59° angle are complementary, so

$\angle 11 +59\°=90\°\\\angle 11=90\°-59\°\\\angle 11=31\°$

Now, angles 11 and 4 are alternate interior angles which are congruent, because a rectangle has opposite congruent and parallel sides.

$\angle 4 = 31\°$

Which means $\angle 3 = 59\°$ , beacuse it's the complement for angle 4.

Now, $\angle 6 = 59\°$ , because it's a base angle of a isosceles triangle. Remember that in a rectangle, diagonals are congruent, and they intersect equally, which creates isosceles triangles.