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3 years ago

What is the answer to (12^2)^3 times 12^-4 and 12^7 times 12^-5 over 12^2

Mathematics

2 answers:

raketka [301]3 years ago

7 0

Answer: 12² = 144

12² ÷ 12² = 1

Step-by-step explanation:

I'll go through it backwards: 12^7 times 12^-5 You subtract the -5 from 7 in the exponents to get 12^2. 12^2 divided by 12^2 is 1.

(12^2)^3 works out to 12^6 because you multiply the exponents when its a power raised by a power. Then you subtract the 4 from the 6 (or add -4 +6) to get 12^2.

That means 12 squared, same as 12 times 12

That's 144.

If you have to multiply the two parts together, It's 144 times 1.

If "and" means "add them together"-- YOU KNOW!

shtirl [24]3 years ago

6 0

Answer:

Step-by-step explanation:

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Which table represents the graph of a logarithmic function in the form y=log3x when b>1?

alex41 [277]

Answer:

The satisfied table of the given function $y = log_{b} (x)$

x 1/8 1/4 1/2 1 2

y -3 -2 -1 0 1

Step-by-step explanation:

Explanation :-

Given logarithmic function $y = log_{b} (x)$ if b >1

Given first table

put x = $\frac{1}{8}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{8} )$

$y = log_{2} (2^{-3} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-3} ) = -3 log_{2} (2) = -3 (1) = -3$

y = -3

ii)

put x = $\frac{1}{4}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{4} )$

$y = log_{2} (2^{-2} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-2} ) = -2 log_{2} (2) = -2 (1) = -2$

y = -2

iii)

put x = $\frac{1}{2}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{2} )$

$y = log_{2} (2^{-1} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-1} ) = -1 log_{2} (2) = - (1) = -1$

y = -1

iv)

put x = 1 given b > 1 so we can choose b = 2

$y = log_{2} (1 )$ = 0

y = 0

v)

put x = $2$ given b > 1 so we can choose b = 2

$y = log_{2} (2 )$

y = 1

Final answer:-

The satisfied table of the given function

x 1/8 1/4 1/2 1 2

y -3 -2 -1 0 1

8 0

3 years ago

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Based on the 2009 season, the Texas Rangers have a winning percentage of .533. Use the binomial model to find the probability th

Naddik [55]

Answer:

0.128

Step-by-step explanation:

We know the probability for any event X is given by,

$P(X=x)=\binom{n}{x}\times p^{n-x}\times q^{x}$ ,

where p is the probability of success and q is the probability of failure.

Here, we are given that p = 0.533.

Since, we have that q = 1 - p

i.e. q = 1 - 0.533

i.e. q = 0.467

It is required to find the probability of 4 wins in the next 5 games i.e. P(X=4) when n = 5.

Substituting the values in the above formula, we get,

$P(X=4)=\binom{5}{4}\times 0.533^{5-4}\times 0.467^{4}$

i.e. $P(X=4)=5 \times 0.533 \times 0.048$

i.e. i.e. $P(X=4)=0.128$

Hence, the probability of 4 wins in the next 5 games is 0.128.

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Oksanka [162]

Answer:

yes that is correct. Do you have a question about it?

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-54 + 108 = Thank you!

julsineya [31]

Answer: 54 and welcome

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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