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3 years ago

What is the answer to (12^2)^3 times 12^-4 and 12^7 times 12^-5 over 12^2

Mathematics

2 answers:

raketka [301]3 years ago

7 0

Answer: 12² = 144

12² ÷ 12² = 1

Step-by-step explanation:

I'll go through it backwards: 12^7 times 12^-5 You subtract the -5 from 7 in the exponents to get 12^2. 12^2 divided by 12^2 is 1.

(12^2)^3 works out to 12^6 because you multiply the exponents when its a power raised by a power. Then you subtract the 4 from the 6 (or add -4 +6) to get 12^2.

That means 12 squared, same as 12 times 12

That's 144.

If you have to multiply the two parts together, It's 144 times 1.

If "and" means "add them together"-- YOU KNOW!

shtirl [24]3 years ago

6 0

Answer:

Step-by-step explanation:

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Read 2 more answers

If the first 4 terms of an infinite geometric sequence are 150, 120, 96, and 76.8, then the sum of all the terms in the sequence

hammer [34]

The sum of the sequence is 750

<h3>How to determine the sum of the series?</h3>

The series is given as:

150, 120, 96, and 76.8,

Start by calculating the common ratio using:

r = T2/T1

This gives

r = 120/150

r = 0.8

The sum of the series is then calculated as:

$S = \frac{a}{1 - r}$

This gives

$S = \frac{150}{1 - 0.8}$

Evaluate

S = 750

Hence, the sum of the sequence is 750