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olga nikolaevna [1]
3 years ago
11

PLEASE PLEASE PLEASE HELP:

Chemistry
1 answer:
My name is Ann [436]3 years ago
6 0
I know the answer but i really don’t
You might be interested in
5 *
Virty [35]

Answer:

A. the charge on their ions

Explanation:

Elements are grouped into the same group in the periodic table if they have the same valence electrons. However, the number of valence electrons an element has, determines the number of charges it can possess.

According to this question, two elements in the same group of the periodic table will have the same charge on their ions because they both have the same number of valence electrons.

5 0
3 years ago
The work of which scientist was most essential to the use of radioactive
fgiga [73]

Answer:

A

Antoine-Laurent Lavoisier

:D

8 0
3 years ago
Someone please help will mark as brainliest
wariber [46]

1. solute is the substance that is being dissolve,while solvent is dissolving medium

2.saturated is solution that contain maximum amount of solut that capable of being dissolve and supersaturated is solution that contain less amount or medium of solut that capable being dissolve : example vinger

3. is a number placed in front of a chemical symbol or formula. It shows how many atoms or molecules of the substance are involved in the reaction. For example, two molecules of hydrogen would be written as 2 H2, and two molecules of water would be written 2 H2O . yes it's can be change only in caseWhen you balance an equation you can only change the coefficients

5 0
3 years ago
If 0.25 mol of HClO2 is added to enough water to prepare a 0.25 M HClO2 aqueous solution, what is the concentration of H3O+(aq)
hammer [34]

Answer:

The concentration of H3O+= 0.15M

Explanation:

From The equation of reaction

HClO2(aq) + H2O(l) ⇌ H3O+(aq) + ClO2−(aq)

0.25mol HClO2(aq) 0.25mol producesClO2−(aq) and x-mol of H3O+

Using Kc = [H3O+][ClO2-]/[HClO2]

0.15= 0.25*x/0.25

Simplify

x=0.15M

5 0
3 years ago
For the following nuclear reaction, what was the beginning radionuclide (X)? X → 86Rn222 + 2He4
BigorU [14]
The original radioisotope underwent double-alpha decay, where the original nucleus lost a total of 4 protons and 4 neutrons.

The original radioisotope would have an atomic number of 86+4 (protons), and would have an atomic mass of 222+8 (protons + neutrons). This would make the element Thorium-230, or 90Th230.
3 0
4 years ago
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