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photoshop1234 [79]
3 years ago
10

For the following nuclear reaction, what was the beginning radionuclide (X)? X → 86Rn222 + 2He4

Chemistry
1 answer:
BigorU [14]3 years ago
3 0
The original radioisotope underwent double-alpha decay, where the original nucleus lost a total of 4 protons and 4 neutrons.

The original radioisotope would have an atomic number of 86+4 (protons), and would have an atomic mass of 222+8 (protons + neutrons). This would make the element Thorium-230, or 90Th230.
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Calculate the number of atoms in 4.8 dm^3 of neon gas at rtp
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No of atoms in 4.8 dm³ of neon gas is determined in the following way.

Explanation:

We have given

Neon Gas=4.8dm³

At STP

1 mole of an ideal gas occupies 22.4 L(dm³) of volume.

which means that  number of molecules occupy 22.4 L of volume.

So

4.8 dm³x 1 mole/22.4 dm³ = 0.214 moles Neon

0.214 moles x 6.02x10²³ atoms/mole = 1.29x10²³ atoms of Neon

No of Atoms in 4.8dm3 neon gas =1.29x10²³ atoms of Neon

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Answer:

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C-Sedimentary

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2 years ago
An object with a mass of 3.2kg has a force of 16.3 newtons to the right and 6.7 newtons to the left applied to it. What is the r
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Answer:

3m/s²

Explanation:

Given parameters:

Mass of object  = 3.2kg

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Force to the left  = 6.7N

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2 years ago
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