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Mars2501 [29]
3 years ago
8

HELP AS SOON AS POSSIBLE NEEDS ANSWERS ASAP

Mathematics
1 answer:
likoan [24]3 years ago
6 0

Answer:

C. The mean will increase and ty e median will remain the same.

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How many solutions can be found for the equation −4x − 11 = 2(x − 3x) + 13? (4 points) none or one or two or infinitrly many
Nadya [2.5K]
There is one solution
5 0
3 years ago
You are playing a game where you draw a card from a standard deck, and you will win $13 if you draw a face card,
marissa [1.9K]

Answer:

Step-by-step explanation:

win

There are 3 face cards / suit. Every suit contains a Jack, Queen, and king.

There are 4 suits so the number of face cards is 3*4 =  12

There is 1 ace / suit

There are 4 suits so the number of aces is 1 * 4 = 4

The gain from the face cards = 12 * 13 = 156

The gain from the aces = 4 * 3 =               12

Total gain = 168

Losses

Any other card costs you $5

How many cards is that? 52 - 16 = 36

Each one costs 5 dollars

Total loss = 5 * 36 = 180

So each time you play the game, you can expect to lose 180 - 68 = 12 dollars. You should walk away quickly from this one.

8 0
2 years ago
PLZ HELP!
9966 [12]

Answer:

The area of the triangle is 36 square units

Step-by-step explanation:

First you can make the graph to set up the problem. You then plot the point 3,6 (A). You then reflect this over the Y axis which would be the point -3,6 (B). Point A is then reflected over the X axis to give you 3,-6 (C). You then multiply their total lengths 12 and 6 which is 72. Then you divide 72 by 2 because it is a triangle to get 36

8 0
3 years ago
Find the seventh term of the
jekas [21]

Answer:

T_7 = \frac{64}{729}

Step-by-step explanation:

Given

a =1

r = \frac{2}{3}

Required

Determine the 7th term

The nth term of a gp is:

T_n = a * r^{n-1

So, we have:

T_7 = 1 * \frac{2}{3}^{7-1

T_7 = 1 * \frac{2}{3}^{6

T_7 = 1 * \frac{2^6}{3^6}

T_7 = 1 * \frac{64}{729}

T_7 = \frac{64}{729}

6 0
3 years ago
If two angles are complementary they add up to
MArishka [77]

Answer:

90 degrees

I hope this helps!

3 0
3 years ago
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