Have to find x,y and z.

A chef is making a sauce at her restaurant. She uses 2 cups of cheese for every 5 cups of cream. what all represents the relatio

shtirl [24]

Answer:

The relationship is Y=2.5X

Step-by-step explanation:

From the sentence

X= 2 and Y= 5

Hence (X/Y) = 2/5

Hence Y= 5X/2 = 2.5X

8 0

3 years ago

A 1991 study at Ataturk University in Turkey showed that 50% of cats were right-pawed, 40% of cats

lawyer [7]

Y Henry psn park Waco psn mic

8 0

3 years ago

Plz quick hurry help !!

tankabanditka [31]

The answer is A. it is 4 multiplied 3 times

6 0

3 years ago

A sales associate farms a neighborhood with 750 homes. The owners seem to list their homes every six years. How many listings sh

jenyasd209 [6]

Answer:

50 homes

Step-by-step explanation:

Given that:

Total Number of homes = 750

Years at which home is listed = 6

Thus average listing per year = (total number of homes / years)

Average listing per year = 750 / 6

Average listing per year = 125 homes

If 40% of homes in the neighborhood can be listed :

0.4 * 125

= 50 homes

8 0

3 years ago

Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. (a) Descr

Daniel [21]

Answer:

(a) The sampling distribution of $\overline{X}$ = Population mean = 79

(b) P ( $\overline{X}$ greater than 81.2 ) = 0.1357

(c) P ( $\overline{X}$ less than or equals 74.4 ) = .0107

(d) P (77.6 less than $\overline{X}$ less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean $(\nu)$ = 79

Standard deviation $(\sigma )$ = 18

(a) Describe the sampling distribution of $\overline{X}$

For large sample using central limit theorem

the sampling distribution of $\overline{X}$ = Population mean = 79

(b) What is Upper P ( $\overline{X}$ greater than 81.2 ) =

$P(\overline{X}> 81.2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})$

= $P(Z> 1.1)$

= $1 - P(Z< 1.1)$

= 1 - .8643 =

= 0.1357

(c) What is Upper P ( $\overline{X}$ less than or equals 74.4 ) =

$P(\overline{X}\leq 74.4)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{74.4- 79}{\frac{18}{\sqrt{81}}})$

= $P(Z\leq -2.3)$

= .0107

(d) What is Upper P (77.6 less than $\overline{X}$ less than 83.2 ) =

$P(77.6< \overline{X}< 83.2)$ = $P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{83.2- 79}{\frac{18}{\sqrt{81}}})$

= $P(- 0.7< Z< 2.1)$

= $(Z< 2.1) - (Z< -0.7)$

= 0.9821 - .2420

= 0.7401

3 0

3 years ago