The answer is 8 because 2x2x2=8
the second one I believe but im not the greatest at math so dont trust me
Answer:

Step-by-step explanation:
Please refer to the attached figure for the labeling and construction in the given figure:
Given that minor angle of arc AB is
.
Or in other words, we can say that angle subtended on the center O by the arc is
.
Now, PA and PB are the tangents so, if we join the center of circle O with A and B, the angles formed are right angles.
i.e.

Now, we know that sum of internal angles of a quadrilateral is equal to
.
Here, we have the quadrilateral AOPB.

Hence, the correct answer is:

Answer:
<em>Q'</em> = (-4, -2)
<em>R' </em>= (4, -2)
<em>S'</em> = (4, 2)
<em>T'</em> = (-4, 2)
Step-by-step explanation:
First, we can create a matrix to scale this rectangle by putting all the x coordinates in the top row and all the y coordinates in the bottom row and multiply it by 4.
Our initial matrix to multiply:
![4\left[\begin{array}{cccc}-1&1&1&-1\\-2&-2&-1&-1\end{array}\right]](https://tex.z-dn.net/?f=4%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-1%261%261%26-1%5C%5C-2%26-2%26-1%26-1%5Cend%7Barray%7D%5Cright%5D)
Moved to the origin:
![4\left[\begin{array}{cccc}-1&1&1&-1\\-0.5&-0.5&0.5&0.5\end{array}\right]](https://tex.z-dn.net/?f=4%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-1%261%261%26-1%5C%5C-0.5%26-0.5%260.5%260.5%5Cend%7Barray%7D%5Cright%5D)
Multiplied by four:
![\left[\begin{array}{cccc}-4&4&4&-4\\-2&-2&2&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-4%264%264%26-4%5C%5C-2%26-2%262%262%5Cend%7Barray%7D%5Cright%5D)
This gives us the points of
<em>Q'</em> = (-4, -2)
<em>R' </em>= (4, -2)
<em>S'</em> = (4, 2)
<em>T'</em> = (-4, 2)
which are our answers.
It would be 55.125 as a decimal, but as a fraction it would be 441/8.