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3 years ago

If an = 2n - 3, then what is the fifth term of the sequence?

Mathematics

2 answers:

Valentin [98]3 years ago

5 0

It’s 7 ... hopes this help

boyakko [2]3 years ago

3 0

Answer:

Step-by-step explanation:

To find the fifth term in the sequence, plug in 5 for n.

a₅=2(5)-3

Then just solve

a₅=10-3

a₅=7

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at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

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2 years ago

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natima [27]

Show that if p(a) ⊂ p(b) then a ⊂ b.

<span>I will assume p() means power set. </span>

<span>proof: let x∈a, then {x} ∈ p(a) and so by hypothesis {x} ∈ p(b). However {x} could not be in p(b) unless x∈b. This shows that each element of a is an element of b and hence a ⊂ b.

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</span>

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3 years ago

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Brilliant_brown [7]

Answer: rational

Step-by-step explanation:

-6 can be written as such an infinite number of ways (just as any rational can be). For example, -6/1, 6/-1, 12/-2, -666/111 and so indeed -6 is rational.

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