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3 years ago

What is the area of the shaded region? PLEASE ANSWER AS SOON AS POSSIBKE

Mathematics

1 answer:

9966 [12]3 years ago

6 0

Answer:

Step-by-step explanation:

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Find 2 a for a = 3 1/4 1) 6 1/2 2) 6 1/4 3) 23 1/4 4) 5 1/2

Nataly_w [17]

Answer:

1) 6 1/2

Step-by-step explanation:

Put 3 1/4 where "a" is and do the arithmetic.

2(3 1/4) = 2·3 + 2·(1/4) = 6 2/4 = 6 1/2

4 0

4 years ago

Which number is not a solution to the inequality below? x<15 A -6 B -2 C 11 D 17 Please help! Thanks

Svetach [21]

Answer:

D.17

Step-by-step explanation:

We are given that inequality

x<15

We have to find the number which is not a solution of the given inequality.

x<15

It means the values of x which is less than 15.

A.-6

-6<15

Therefore, it is the solution of given inequality.

B.-2

-2<15

Therefore, it is the solution of given inequality.

C.11

11<15

Therefore, it is the solution of given inequality.

D.17

17>15

Therefore, it is not a solution of given inequality.

Option D is true.

6 0

3 years ago

The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in fourth quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$