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Anna007 [38]
3 years ago
6

How many solutions will there be to the following equation?

Mathematics
1 answer:
Akimi4 [234]3 years ago
7 0

Answer:

C. 1 solution

Step-by-step explanation:

I calculated logically

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4(n-1)+2 = -23 +7n
liubo4ka [24]

Answer:

<h2><em><u>n</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em></h2>

Step-by-step explanation:

4(n-1)+2 = -23 +7n

=> 4n - 4 + 2 = - 23 + 7n

=> 23 - 4 + 2 = 7n - 4n

=> 21 = 3n

=  > n =  \frac{21}{3}

=> <em><u>n</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>7</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

6 0
3 years ago
What is the volume of the rectangular prism​
drek231 [11]

Answer:

Step-by-step explanation:

V=WHL

8 0
3 years ago
Read 2 more answers
Look at this equation: x2 - 29x - 132 = 0. What is the factored form of this equation?
Lady_Fox [76]
Use the commutative property to reorder the terms

2x-29x-132=0

Next step

Collect like terms

-27x-132=0

Move the constant to the right-hand side and change its sign

-27x=132

Divide both sides of the equation by

Solution or answer ———
X= - 44/9

Alternative form <———
X =-4 8/9 ,x=-4.8

Any of those are the answer

3 0
3 years ago
For f(x)=4x+1 and g(x)=(x^2)-5, find (f-g)(x).
Harrizon [31]

f(x)=4x+1,\ g(x)=x^2-5\\\\(f-g)(x)=f(x)-g(x)\\\\(f-g)(x)=(4x+1)-(x^2-5)=4x+1-x^2-(-5)\\\\=4x+1-x+5=-x^2+4x+(1+5)\\\\=\boxed{(f-g)(x)=-x^2+4x+6}

8 0
3 years ago
How many different ways are there to arrange the letters of the word MATH?
Dominik [7]

Answer:

More than 20. I'll be more precise. There are 24 ways.

4 0
3 years ago
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