F(q)=2q+3... This is the equation in a function notation with q as the independent variable
Answer:
10 liters of orange juice, 5 liters of champagne
Step-by-step explanation:
We can call the amount of orange juice and champagne as x and 15 - x liters respectively. Then, we can write the following equation:
1.50 * x + 12 * (15 - x) = 5 * 15
1.5x + 180 - 12x = 75
-10.5x + 180 = 75
-10.5x = -105
x = 10 so 15 - x = 15 - 10 = 5.
Answer:
80
Step-by-step explanation:
2.5(2+2) x (2^2+2^2)
2.5(4) x (4+4)
10 x 8
80
your answer is 80 :)
Solution :
Given :
![$n_1 = n_2 = 40$](https://tex.z-dn.net/?f=%24n_1%20%3D%20n_2%20%3D%2040%24)
![$\overline X_1 = 18$](https://tex.z-dn.net/?f=%24%5Coverline%20X_1%20%3D%2018%24)
![$S_1 = 4$](https://tex.z-dn.net/?f=%24S_1%20%3D%204%24)
![$\overline X_2 = 12$](https://tex.z-dn.net/?f=%24%5Coverline%20X_2%20%3D%2012%24)
![$S_2 =10$](https://tex.z-dn.net/?f=%24S_2%20%3D10%24)
So we want to test :
vs ![$H_1 : \mu_1 \neq \mu_2 $](https://tex.z-dn.net/?f=%24H_1%20%3A%20%5Cmu_1%20%5Cneq%20%5Cmu_2%20%24)
a). For 98% confidence interval :
![$=\left((\overline X_1 - \overline X_2) \pm Tn_1+n_2-2, \alpha / 2 \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}\right)$](https://tex.z-dn.net/?f=%24%3D%5Cleft%28%28%5Coverline%20X_1%20-%20%5Coverline%20X_2%29%20%5Cpm%20Tn_1%2Bn_2-2%2C%20%5Calpha%20%2F%202%20%5Csqrt%7B%5Cfrac%7Bs_1%5E2%7D%7Bn_1%7D%2B%5Cfrac%7Bs_2%5E2%7D%7Bn_2%7D%7D%5Cright%29%24)
![$=\left((18-12) \pm 2.375 \sqrt{\frac{4^2}{40}+\frac{10^2}{40}}\right)$](https://tex.z-dn.net/?f=%24%3D%5Cleft%28%2818-12%29%20%5Cpm%202.375%20%5Csqrt%7B%5Cfrac%7B4%5E2%7D%7B40%7D%2B%5Cfrac%7B10%5E2%7D%7B40%7D%7D%5Cright%29%24)
![$=(6 \pm 4.0445)$](https://tex.z-dn.net/?f=%24%3D%286%20%5Cpm%204.0445%29%24)
= (1.956, 10.045)