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mars1129 [50]
3 years ago
14

÷

id="TexFormula1" title="\lim_{x\to \ 0^{+} } (1+x)^{\frac{4}{x} }" alt="\lim_{x\to \ 0^{+} } (1+x)^{\frac{4}{x} }" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Drupady [299]3 years ago
5 0

Answer:

e^4

Step-by-step explanation:

\text{Let L=} \lim_{x \to 0+} (1+x)^{4/x}

Take log both sides

\log{L}= \lim_{x \to 0+} \frac{4\times log(1+x)}{x}\\\text{Apply L'Hopital}\\\log{L}=\lim_{x \to 0+} \frac{4\times 1}{1+x}\\\log{L}=4\\L=e^4

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