Answer:
a b e
Step-by-step explanation:
not sure could be wrong
Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of
(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min
and flows out at a rate of
(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min
Then the net flow rate is governed by the differential equation
Solve for S(t):
The left side is the derivative of a product:
![\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Be%5E%7Bt%2F800%7DS%28t%29%5Cright%5D%3D%5Cdfrac8%7B100%7De%5E%7Bt%2F800%7D)
Integrate both sides:
There's no sugar in the water at the start, so (a) S(0) = 0, which gives
and so (b) the amount of sugar in the tank at time t is
As 
, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.
If the number begins by being rational, multiplying by 0.5 will not change whether or not it is rational. It will remain rational.
That would include any even number 12 * 0.5 = 6
12 started out as rational, so the answer is rational (6)
Any odd number is also rational
23 * 0.5 = 11.5
23 and 11.5 are both rational.
3.636363636 ... is rational so when multiplied by 0.5 the result will be rational.
1.818181818....
So if we start with something irrational like pi
then pi * 0.5 is not rational.
If you have choices, please list them.
9514 1404 393
Answer:
RS = √(b² +(c -a)²)
Step-by-step explanation:
Put the given point coordinates in the given formula:
- R = (x₁, y₁) = (0, a)
- S = (x₂, y₂) = (b, c)
RS = √((b -0)² +(c -a)²)
RS = √(b² +(c -a)²)
