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3 years ago

What is the measure of angle M?

Mathematics

1 answer:

Nesterboy [21]3 years ago

3 0

Answer:

35°

Step-by-step explanation:

4x+11 = 5x-24

5x-4x=x

x=24+11

x=35

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A sheet of paper 90 cm-by-66 cm is made into an open box (i.e. there's no top), by cutting x-cm squares out of each corner and f

NNADVOKAT [17]

Answer:

$26 - \sqrt{181}$ cm

Step-by-step explanation:

The volume of the box is:

V = height * length * width

V = x*(66 - 2*x)*(90 - 2*x)

V = (66*x - 2*x^2)*(90 - 2*x)

V = 5940*x - 132*x^2 - 180*x^2 + 4*x^3

V = 4*x^3 - 312*x^2 + 5940*x

where x is the length of the sides of the squares, in cm.

The mathematical problem is :

Maximize: V = 4*x^3 - 312*x^2 + 5940*x

subject to:

x > 0

2*x < 66 <=> x < 33

In the maximum, the first derivative of V, dV/dx, is equal to zero

dV/dx = 12*x^2 - 624*x + 5940

From quadratic formula

$x = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}$

$x = \frac{624 \pm \sqrt{(-624)^2 - 4(12)(5940)}}{2(12)}$

$x = \frac{624 \pm \sqrt{104256}}{24}$

$x = \frac{624 \pm \sqrt{2^6*3^2*181}}{24}$

$x = \frac{624 \pm 8*3*\sqrt{181}}{24}$

$x_1 = \frac{624 + 24*\sqrt{181}}{24}$

$x_1 = 26 + \sqrt{181}$

$x_2 = \frac{624 - 24*\sqrt{181}}{24}$

$x_2 = 26 - \sqrt{181}$

But $x_1 > 33$ , then is not the correct answer.

5 0

3 years ago

For what values of x is XP 36-5x true?

KiRa [710]

I am not sure this is the answer but I believe it’s 4 and -9

4 0

3 years ago

The nature park has a pride of 7 adult lions and 4 cubs. The adults eat 6 pounds of meat each day and the cubs eat 3 pounds. Sim

Mademuasel [1]

Answer:

7 x 6 = 42, 42+ 4 x 3, 4 x 3 is 12, 42 + 12 = 54

Step-by-step explanation:

Hope I helped pls give brainliest

8 0

2 years ago

Water is leaking out of an inverted conical tank at a rate of 6800.0 cubic centimeters per min at the same time that water is be

m_a_m_a [10]

Answer:

6.82 $mt^3/min$

Step-by-step explanation:

By congruence of triangles, the radius r of the cone base when its height is 1 meter satisfies the relation

r/1 = 2.5/6

(See picture attached)

So, r = 0.4166 meters when the water is 1 meter high.

The volume of a cone with radius of the base = R is given by

$V=\frac{\pi R^2h}{3}$

So, the volume of water when it is 1 meter high is

$V=\frac{\pi* 0.(4166)^2}{3}=0.1817\;mt^3$

One minute later, the height of the water is 1 meter + 30 centimeters = 1.30 mt

The radius now satisfies

r/1.3 = 2.5/6

and now the radius of the base is

r = 0.5416 mt

and the new volume of water is $0.3071\;mt^3$

So, the water is raising at a speed of

0.3071-0.1871 = 0.12 $mt^3/min$

This speed equals the difference between the water being pumped and the water leaking,

So,

<em>0.12 = Speed of water being pumped -6.8 </em>

and

Speed of water being pumped = 6.8+0.12 = 6.82 $mt^3/min$

8 0

3 years ago

Find the derivative of cscx/3sinx

Neporo4naja [7]

$\frac{csc x}{3sinx} = \frac{1}{3sin ^{2}x }$

3 0

3 years ago