Answer:
1. (1,1) (2,6) (3, 11)
2. Yes
Step-by-step explanation:
1. 5(1)-4 = 5-4 = 1
5(2)-4 = 10-4 = 6
5(3)-4 = 15-4 = 11
(I just chose 3 simple x values and plugged them into the equation to get the y values then wrote it as an ordered pair)
2. 5(-5)-4 = -25-4 = -29
-29 = -29
(Same as number 1 but I used the given x value then I checked if the y value I got matched the ordered pair)
y = 5x - 4
When x = 0, y = 5(0) - 4 = -4.
When x = 1, y = 5(1) - 4 = 1.
When x = 2, y = 5(2) - 4 = 6.
The 3 ordered pairs we have are (0,-4), (1,1) and (2,6).
We now check the point (-5,-29):
(-29) : 5(-5) - 4
-29 : -25 - 4
-29 : -29 => -29 = -29.
Since Left hand side = Right hand side, the point (-5,-29) is a solution.
hello :
3b^4−6b^2+27b = 3b(b^3-2b+9)
12:9
x = 31, x = 19
<em>The numbers are 4 and 6</em>
<em />
Let
x------> be the first positive even integer
x+2---> be the second positive even integer
<em>we know that the solution is a positive value</em>
<u>The numbers are 4 and 6</u>
Hope this helps!
<em>stay safe</em>
