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3 years ago

Two elves can make 5 toys in 10 minutes How many toys can four elves make in 30 minutes?

Mathematics

2 answers:

vredina [299]3 years ago

7 0

Answer:

Step-by-step explanation:

two elves 5 toys 10 minutes

four elves 10 toys 10 minutes

four elves 30 toys 30 minutes

4vir4ik [10]3 years ago

6 0

30 toys in 30. Minutes. Math: 2x2= 4. 4x5=20+10

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What is the volume of a rectangular storage container with a LENGTH of 2.5 ft, a WIDTH of 1 ft, and a HEIGHT of 2 ft? Question 1

solong [7]

A is the correct answer
$2.5 \times 1 \times 2 = 5 {ft}^{3}$

good luck

5 0

3 years ago

which of these shows the result of using the first equation to substitute for y in the second equation, then combining like term

Furkat [3]

Answer:

C. $\Rightarrow \bold{8x = 16}$

Step-by-step explanation:

Given the two equations:

$y=2x ........ (1)\\ 2x+3y=16.......(2)$

To find:

The correct option when value of y is substituted to 2nd equation using the 1st equation.

Solution:

First of all, let us learn about the substitution method.

Substitution method is the method to provide solutions to two variables when we have two equations and two variables.

In substitution method, we find the value of one variable in terms of the other variable and put this value in the other equation.

Now, the other equation becomes only single variable and then we solve for the variable's value.

Here, we have two equations and value of one varible is:

$y=2x$

Let us put value of y in 2nd equation:

$2x+3y=16\\\Rightarrow 2x + 3(2x) = 16\\\Rightarrow 2x + 6x = 16\\\Rightarrow \bold{8x=16}$

So, the correct answer is option C. $\Rightarrow \bold{8x = 16}$

7 0

3 years ago

In the circle below, suppose m FEH=272º and m EFG=116º. Find the following.

adoni [48]

Answer:

m∠FEH = 44°

m∠EHG = 64°

Step-by-step explanation:

1) The given information are;

The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°

Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°

Therefore, angle subtended by arc ∠HGF at the center = 88°

The angle subtended by arc ∠HGF at the circumference = m∠FEH

∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)

m∠FEH = 44°

2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°

The sum of angles in a quadrilateral = 360°

Therefore;

m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)

m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°

m∠EHG = 64°.

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3 years ago

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Tomtit [17]

I believe the answer would be d.6

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3 years ago

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