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DaniilM [7]
3 years ago
10

Can someone help me with the 2 highlighted questions?

Mathematics
1 answer:
dexar [7]3 years ago
4 0

Answer:

2. domain: {3,4,5,6,7}; range: {2,3,4,5,6}

4. IS a function

Step-by-step explanation:

2. The <em>domain</em> is the list of first numbers of each pair.

The <em>range</em> is the list of second numbers.

4. If each value on the left only has <em>one arrow</em> coming from it, the relation <u>is</u> a function. That is the case here.

__

Contrast that to the problem above (3.). In that one, the number 4 1/2 has two arrows coming from it. That relation is NOT a function.

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Factorise the following:<br><img src="https://tex.z-dn.net/?f=%7B3x%7D%5E%7B2%7D%20%20%2B%205x%20-%2012" id="TexFormula1" title=
Fed [463]

Answer:

(x + 3)(3x - 4)

Step-by-step explanation:

Given

3x² + 5x - 12

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 12 = - 36 and sum = + 5

The factors are + 9 and - 4

Use these factors to split the x- term

3x² + 9x - 4x - 12 ( factor first/second and third/fourth terms )

= 3x(x + 3) - 4(x + 3) ← factor out (x + 3) from each term

= (x + 3)(3x - 4)

Thus

3x² + 5x - 12 = (x + 3)(3x - 4) ← in factored form

6 0
3 years ago
What is -10 times 100 to the 10 power
Lyrx [107]
Bruh............................
7 0
3 years ago
Read 2 more answers
The base of a solid in the first quadrant of the xy plane is a right triangle bounded by the coordinate axes and the line x + y
Ivahew [28]

The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is 

(x - x^2)^2 * sqrt(3)/4. 

Integrating from x = 0 to x = 1, we have 

[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4 

= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144. 

Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...

8 0
3 years ago
What is the simplified form of the expression? (m^-1m^5/m^-2)^-3
Eva8 [605]
1 (((m^(-1)) (m^5)) / (m^(-2)))^(-3) =1/m^18
5 0
3 years ago
Read 2 more answers
In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.
Tema [17]

Answer:

Area  \approx 1149\ cm^2

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to \angle W)

Side u = 83 cm (It is the side opposite to \angle U)

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

A = \dfrac{1}{2}\times a\times b\times sinC

Where a and b are the two sides and

\angle C is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A  \approx 1149\ cm^2

So, the <em>area </em>of given triangle to the nearest square centimetre is:

Area  \approx 1149\ cm^2

8 0
3 years ago
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