Part (b)
We use the result of part (a) and plug in (x,y) = (0,0). This is directly from the initial condition y(0) = 0.

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This means,

is the solution with the initial condition y(0) = 0.
Answer:72 IS THE ANSWER
Step-by-step explanation:
BRAINLIEST????? PLEASE
Answer:
The minimum score required for an A grade is 83.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 72.3 and a standard deviation of 8.
This means that 
Find the minimum score required for an A grade.
This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.




The minimum score required for an A grade is 83.
Because they are the same equation, just rewritten in a different way.
s = 4p
divide both sides by 4 to get the other equation:
(1/4)s = p
A the 12 pack box of 1.4 ounce bars