Conner scored 4,370 points in a game.Amy scored 1,089 fewer points then Conner how many points did Amy scored

1 answer:

3 0

SOLUTION:

Connor's score = 4, 370 points

Amy's score = Connor's score - 1, 089

Amy's score = 4, 370 - 1089

Amy's score = 3, 281 points

Therefore, Amy scored 3, 281 points.

Hope this helps! :)
Have a lovely day! <3

You might be interested in

Create a word problem that could be solved using the expression (−12) + (32) + (−16). Also, show the solution.

SCORPION-xisa [38]

Answer:

Joe is at Walmart shopping for Pokemon cards. His mother gave him $32 dollars to buy any toys he wants. He plans to spend $16 to buy booster packs and $12 for barbies for his sister. How much money does he have left?

Step-by-step explanation:

Solution: 32-12-16=4

Joe has $4 left.

4 0

3 years ago

Which statement about this figure is true?

Arisa [49]

Answer: I'm thinking it's reflectional symmetry.

Step-by-step explanation:

3 0

4 years ago

1. Which of the following is the square of a binomial? O a2 + b2 O 16x2 +9y2 O m2-mn + n2 O c2-2cd+d2

melomori [17]

Answer:

i guess it's the second one, 16x2+9y2, since they are both raised to 2 and they are binomial

6 0

3 years ago

What is the Coefficient in <br> 3x + 7

alexandr1967 [171]

3 is the coefficient

5 0

3 years ago

Read 2 more answers

Does anyone know the answer to this one?

polet [3.4K]

Answer:

$\large\boxed{a(x+4)(x-5)=0,\ a\in\mathbb{R}-\{0\}}\\\\\text{for}\ a=1\to\boxed{x^2-x-20=0}$

Step-by-step explanation:

$\text{If}\ x_1\ \text{and}\ x_2\ \text{are the roots of the quadratic equation}\ ax^2+bx+c=0,\\\text{then}\ ax^2+bx+c=a(x-x_1)(x-x_2).\\\\\text{If}\ x_1\ \text{and}\ x_2\ \text{, then they are the roots of the quadratic equation.}\\\\\text{We have}\ x_1=-4\ \text{and}\ x_2=5.\ \text{Therefore we have the equation:}\\\\a(x-(-4))(x-5)=0\\\\a(x+4)(x-5)=0\qquad\text{for any value of}\ a\ \text{except 0}.$

7 0

3 years ago